Solution For (3x-7)(4x-3)=(6x-4)(2x-5) Equation

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(3x-7)(4x-3)=(6x-4)(2x-5)

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Solution for (3x-7)(4x-3)=(6x-4)(2x-5) equation:

(3x-7)(4x-3)=(6x-4)(2x-5) We move all terms to the left: (3x-7)(4x-3)-((6x-4)(2x-5))=0 We multiply parentheses .. (+12x^2-9x-28x+21)-((6x-4)(2x-5))=0 We calculate terms in parentheses: -((6x-4)(2x-5)), so: (6x-4)(2x-5) We multiply parentheses .. (+12x^2-30x-8x+20) We get rid of parentheses 12x^2-30x-8x+20 We add all the numbers together, and all the variables 12x^2-38x+20 Back to the equation: -(12x^2-38x+20) We get rid of parentheses 12x^2-12x^2-9x-28x+38x+21-20=0 We add all the numbers together, and all the variables x+1=0 We move all terms containing x to the left, all other terms to the right x=-1

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