Algebra InputsTrigonometry InputsCalculus InputsMatrix Inputs Basic algebra trigonometry calculus statistics matrices CharactersSolve for x x=\frac{4y-z-4}{5}View solution stepsSteps for Solving Linear Equation 5 x - 4 y + z = - 4 Add 4y to both sides. 5x+z=-4+4y Subtract z from both sides. 5x=-4+4y-z The equation is in standard form. 5x=4y-z-4 Divide both sides by 5. \frac{5x}{5}=\frac{4y-z-4}{5} Dividing by 5 undoes the multiplication by 5. x=\frac{4y-z-4}{5} Solve for y y=\frac{5x+z+4}{4}View solution stepsSteps for Solving Linear Equation 5 x - 4 y + z = - 4 Subtract 5x from both sides. -4y+z=-4-5x Subtract z from both sides. -4y=-4-5x-z The equation is in standard form. -4y=-5x-z-4 Divide both sides by -4. \frac{-4y}{-4}=\frac{-5x-z-4}{-4} Dividing by -4 undoes the multiplication by -4. y=\frac{-5x-z-4}{-4} Divide -4-5x-z by -4. y=\frac{z}{4}+\frac{5x}{4}+1 QuizLinear Equation5 problems similar to: 5 x - 4 y + z = - 4
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How do you solve \displaystyle{x}={7}{y}+{7} and \displaystyle-{4}{x}+{4}{y}=-{16} ?https://socratic.org/questions/how-do-you-solve-x-7y-7-and-4x-4y-16 I found: \displaystyle{x}=\frac{{7}}{{2}} \displaystyle{y}=-\frac{{1}}{{2}} Explanation: You can substitute for \displaystyle{x} the first equation into the second to get: \displaystyle-{4}{\left({7}{y}+{7}\right)}+{4}{y}=-{16} ... How do you solve the system \displaystyle{x}-{4}{y}+{4}{z}=-{1} , \displaystyle{y}-{3}{z}={5} , and \displaystyle{3}{x}-{4}{y}+{6}{z}={1} ?https://socratic.org/questions/how-do-you-solve-the-system-x-4y-4z-1-y-3z-5-and-3x-4y-6z-1 \displaystyle{x}={3} , \displaystyle{y}=-{1} and \displaystyle{z}=-{2} Explanation: Perform the Gauss Jordan elimination on the augmented matrix \displaystyle{A}={\left(\begin{array}{ccc|c} {1}&-{4}&{4}&-{1}\\{0}&{1}&-{3}&{5}\\{3}&-{4}&{6}&{1}\end{array}\right)} ... How do you solve \displaystyle-{5}{x}-{4}{y}=-{48} and \displaystyle-{3}{x}+{2}{y}={2} using substitution?https://socratic.org/questions/how-do-you-solve-5x-4y-48-and-3x-2y-2-using-substitution \displaystyle{x}={4} Explanation: \displaystyle-{5}{x}-{4}{y}=-{48}\ \text{ (1)} \displaystyle-{3}{x}+{2}{y}={2}\ \text{ }\ {2}{y}={2}+{3}{x}\ \text{ }\ {\left({2}\cdot\right)}{2}{y}={\left({2}\cdot\right)}{\left({2}+{3}{x}\right)} ... How do you solve the system \displaystyle{5}{x}-{4}{y}+{2}{z}={21} , \displaystyle-{x}-{5}{y}+{6}{z}=-{24} , and \displaystyle-{x}-{4}{y}+{5}{z}=-{21} ?https://socratic.org/questions/how-do-you-solve-the-system-5x-4y-2z-21-x-5y-6z-24-and-x-4y-5z-21 Please see the explanation for the matrix row operations. \displaystyle{x}={5},{y}=-{1} and \displaystyle{z}=-{4} Explanation: Write the row for −x − 5y + 6z = −24 into an augmented ... How do you solve the system \displaystyle{x}-{2}{y}+{8}{z}=-{4} , \displaystyle{x}-{2}{y}+{6}{z}=-{2} , \displaystyle{2}{x}-{4}{y}+{19}{z}=-{11} ?https://socratic.org/questions/how-do-you-solve-the-system-x-2y-8z-4-x-2y-6z-2-2x-4y-19z-11 \displaystyle{\left({x},{y},{z}\right)}={t}{V}+{W},\forall{t}\in\mathbb{R} Explanation: \displaystyle{\left(\begin{array}{ccc} {1}&-{2}&{8}\\{1}&-{2}&{6}\\{2}&-{4}&{19}\end{array}\right)}\cdot{\left(\begin{array}{c} {x}\\{y}\\{z}\end{array}\right)}={\left(\begin{array}{c} -{4}\\-{2}\\-{11}\end{array}\right)} ... How do you solve using gaussian elimination or gauss-jordan elimination, \displaystyle{x}-{2}{y}+{z}=-{14} , \displaystyle{y}-{2}{z}={7} , \displaystyle{2}{x}+{3}{y}-{z}=-{1} ?https://socratic.org/questions/how-do-you-solve-using-gaussian-elimination-or-gauss-jordan-elimination-x-2y-z-1-1 \displaystyle{x}=\frac{{80}}{{7}} , \displaystyle{y}=-\frac{{345}}{{7}} and \displaystyle{z}=-{124} Explanation: From \displaystyle{x}-{2}{y}+{z}=-{14} , \displaystyle{z}={2}{y}-{x}-{14} ...More Items
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CopyCopied to clipboard5x+z=-4+4y Add 4y to both sides.5x=-4+4y-z Subtract z from both sides.5x=4y-z-4 The equation is in standard form.\frac{5x}{5}=\frac{4y-z-4}{5} Divide both sides by 5.x=\frac{4y-z-4}{5} Dividing by 5 undoes the multiplication by 5.-4y+z=-4-5x Subtract 5x from both sides.-4y=-4-5x-z Subtract z from both sides.-4y=-5x-z-4 The equation is in standard form.\frac{-4y}{-4}=\frac{-5x-z-4}{-4} Divide both sides by -4.y=\frac{-5x-z-4}{-4} Dividing by -4 undoes the multiplication by -4.y=\frac{z}{4}+\frac{5x}{4}+1 Divide -4-5x-z by -4.
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Quadratic equation { x } ^ { 2 } - 4 x - 5 = 0Trigonometry 4 \sin \theta \cos \theta = 2 \sin \thetaLinear equation y = 3x + 4Arithmetic 699 * 533Matrix \left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]Simultaneous equation \left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.Differentiation \frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }Integration \int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d xLimits \lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}Back to top
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View solution stepsSteps for Solving Linear Equation 5 x - 4 y + z = - 4 Add 4y to both sides. 5x+z=-4+4y Subtract z from both sides. 5x=-4+4y-z The equation is in standard form. 5x=4y-z-4 Divide both sides by 5. \frac{5x}{5}=\frac{4y-z-4}{5} Dividing by 5 undoes the multiplication by 5. x=\frac{4y-z-4}{5} Solve for y y=\frac{5x+z+4}{4}
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