Solve 5x - 6y = -38 And 3x + 4y = 0. (4, 3) - Cuemath
Solution:
Given:
Two equations are 5x - 6y = -38 and 3x + 4y = 0
The equations are in the form of ax + by + c = 0
In order to solve, we need to make the coefficients equal to that one arbitrary constant gets cancelled.
Let 5x - 6y = -38 --- (1)
and 3x + 4y = 0 --- (2)
Multiply equation (1) with 3, we get
⇒ 3(5x - 6y) = -38
⇒ 15x - 18y = -114 --- (3)
Multiply equation (2) with 5, we get 5(3x + 4y ) = 0
⇒ 15x + 20y = 0 --- (4)
Now,
Subtract (4) from (3)
We get, -38y = -114
⇒ 38y = 114
⇒ y = 114/38
⇒ y = 3
Put y = 3 in eq (2), we get
⇒ 3x + 4y = 0
⇒ 3x + 4(3) = 0
⇒ 3x = -12
⇒ x = -4
The solution set for the given equations 5x - 6y = -38 and 3x + 4y = 0 is (-4, 3).
Solve 5x - 6y = -38 and 3x + 4y = 0
Summary:
By solving 5x - 6y = -38 and 3x + 4y = 0, we get x = -4 and y = 3.
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