Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1 ... - Cuemath
Solution:
We will use the concepts of fractions to solve this.
(a) 2/3 + 1/7 LCM of 3 and 7 = 21 (2 × 7 + 1 × 3) / 21 = (14 + 3) / 21 = 17/21
(b) 3/10 + 7/15 LCM of 10 and 15 = 30 = (3 × 3 + 7 × 2) / 30 = (14 + 9) / 30 = 23/30
(c) 4/9 + 2/7 LCM of 9 and 7 = 63 = (4 × 7 + 2 × 9) / 63 = (28 + 18) / 63 = 46/63
(d) 5/7 + 1/3 LCM of 7 and 3 = 21 = (5 × 3 + 1 × 7) / 21 = (15 + 7) / 21 = 22/21
(e) 2/5 + 1/6 LCM of 5 and 6 = 30 = (2 × 6 + 1 × 5) / 30 = (12 + 5) / 30 = 17/30
(f) 4/5 + 2/3 LCM of 5 and 3 = 15 = (4 × 3 + 5 × 2) / 15 = (12 + 10) / 15 = 22/15
(g) 3/4 - 1/3 LCM of 4 and 3 = 12 = (3 × 3 + 1 × 4) / 12 = (9-4) / 12 = 5/12
(h) 5/6 - 1/3 LCM of 6 and 3 = 6 = (1 × 5 - 1 × 2) / 6 = (5 - 2) / 6 = 3/6 = 1/2
(i) 2/3 + 3/4 + 1/2 LCM of 3,4 and 2 = 12 = (2 × 4 + 3 × 3 + 1 × 6) /12 = (8 + 9 + 6) / 12 = 23 / 12
(j) 1/2 + 1/3 + 1/6 LCM of 2,3 and 6 = 6 = (1 × 3 + 1 × 2 + 1 × 1) / = (3 + 2 + 1) / 6 = 6 / 6 = 1
(k) \(1{\dfrac{1}{3}}\) + \(3{\dfrac{2}{3}}\) = 1 + 1/3 + 3 + 2/3 = 4 + 1/3 + 2/3 = 4 + 1/3 + 2/3 = 4 + 3/3 = 4 + 1 = 5
(l) \(4{\dfrac{2}{3}}\) + \(3{\dfrac{1}{4}}\) = 4 + 2/3 + 3 + 1/4 = 7 + 2/3 + 1/4 = 7 + (2 × 4 + 1 × 3) / 12 = 7 + 11/12 = 95 / 12
(m) 16/5 - 7/5 = 16 × 1 - 7 × 1 = (16 - 7) / 5 = 9 / 5
(n) 4/3 - 1/2 = (4 × 2 - 1 × 3) / 6 = (8 - 3) / 6 = 5 / 6
You can also use the Fraction Calculator to check your answer.
NCERT Solutions for Class 6 Maths Chapter 7 Exercise 7.6 Question 1
Solve (a) 2/3 + 1/7 (b) 3/10 + 7/15 (c) 4/9 + 2/7 (d) 5/7 + 1/3 (e) 2/5 + 1/6 (f) 4/5 + 2/3 (g) 3/4 - 1/3 (h) 5/6 - 1/3 (i) 2/3 + 3/4 + 1/2 (j) 1/2 + 1/3 + 1/6 (k) \(1{\dfrac{1}{3}}\) + \(3{\dfrac{2}{3}}\) (l) \(4{\dfrac{2}{3}}\) + \(3{\dfrac{1}{4}}\) (m) 16/5 - 7/5 (n) 4/3 - 1/2
Summary:
The required answer for all the given problems is a. 17/21 b. 23/30 c. 46/63 d. 22/21 e. 17/30 f. 22/15 g. 5/12 h. 1/2 i. 23/12 j.1 k. 5 l. 95/12 m. 9/5 n. 5/6
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