Solve Approximation X4-2x3-5x2+1=0 Tiger Algebra Solver

Reformatting the input :

Changes made to your input should not affect the solution: (1): "x2" was replaced by "x^2". 2 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((x4)-(2•(x3)))-5x2)+1 = 0

Step 2 :

Equation at the end of step 2 :

(((x4) - 2x3) - 5x2) + 1 = 0

Step 3 :

Checking for a perfect cube :

3.1 x4-2x3-5x2+1 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: x4-2x3-5x2+1 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: -5x2+1 Group 2: x4-2x3 Pull out from each group separately :Group 1: (-5x2+1) • (1) = (5x2-1) • (-1)Group 2: (x-2) • (x3)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

3.3 Find roots (zeroes) of : F(x) = x4-2x3-5x2+1Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 1 and the Trailing Constant is 1. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 Let us test ....

P	Q	P/Q	F(P/Q)	Divisor
-1	1	-1.00	-1.00
1	1	1.00	-5.00

Polynomial Roots Calculator found no rational roots

Equation at the end of step 3 :

x4 - 2x3 - 5x2 + 1 = 0

Step 4 :

Quartic Equations :

4.1 Solve x4-2x3-5x2+1 = 0In search of an interavl at which the above polynomial changes sign, from negative to positive or the other wayaround.Method of search: Calculate polynomial values for all integer points between x=-20 and x=+20 Found change of sign between x= -2.00 and x= -1.00

Approximating a root using the Bisection Method :

We now use the Bisection Method to approximate one of the solutions. The Bisection Method is an iterative procedure to approximate a root (Root is another name for a solution of an equation).The function is F(x) = x4 - 2x3 - 5x2 + 1At x= -1.00 F(x) is equal to -1.00 At x= -2.00 F(x) is equal to 13.00 Intuitively we feel, and justly so, that since F(x) is negative on one side of the interval, and positive on the other side then, somewhere inside this interval, F(x) is zero Procedure :(1) Find a point "Left" where F(Left) < 0(2) Find a point 'Right' where F(Right) > 0(3) Compute 'Middle' the middle point of the interval [Left,Right](4) Calculate Value = F(Middle)(5) If Value is close enough to zero goto Step (7) Else : If Value < 0 then : Left <- Middle If Value > 0 then : Right <- Middle(6) Loop back to Step (3)(7) Done!! The approximation found is MiddleFollow Middle movements to understand how it works :

Left Value(Left) Right Value(Right) -1.000000000 -1.000000000 -2.000000000 13.000000000 -1.000000000 -1.000000000 0.000000000 1.000000000 -1.000000000 -1.000000000 -0.500000000 0.062500000 -0.750000000 -0.652343750 -0.500000000 0.062500000 -0.625000000 -0.312255859 -0.500000000 0.062500000 -0.562500000 -0.125961304 -0.500000000 0.062500000 -0.531250000 -0.031615257 -0.500000000 0.062500000 -0.531250000 -0.031615257 -0.515625000 0.015518248 -0.523437500 -0.008035358 -0.515625000 0.015518248 -0.523437500 -0.008035358 -0.519531250 0.003745463 -0.521484375 -0.002144034 -0.519531250 0.003745463 -0.521484375 -0.002144034 -0.520507812 0.000800954 -0.520996094 -0.000671482 -0.520507812 0.000800954 -0.520996094 -0.000671482 -0.520751953 0.000064751 -0.520874023 -0.000303362 -0.520751953 0.000064751 -0.520812988 -0.000119304 -0.520751953 0.000064751 -0.520782471 -0.000027276 -0.520751953 0.000064751 -0.520782471 -0.000027276 -0.520767212 0.000018737 -0.520774841 -0.000004269 -0.520767212 0.000018737 -0.520774841 -0.000004269 -0.520771027 0.000007234 -0.520774841 -0.000004269 -0.520772934 0.000001482

Next Middle will get us close enough to zero: F( -0.520773411 ) is 0.000000044 The desired approximation of the solution is: x ≓ -0.520773411 Note, ≓ is the approximation symbol

One solution was found :

x ≓ -0.520773411