Solve Polynomiallongdivision 2x^4+5x^3-7x-4 Tiger Algebra Solver
Step 1 :
Equation at the end of step 1 :
(((2 • (x4)) + 5x3) - 7x) - 4Step 2 :
Equation at the end of step 2 :
((2x4 + 5x3) - 7x) - 4Step 3 :
Checking for a perfect cube :
3.1 2x4+5x3-7x-4 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 2x4+5x3-7x-4 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: -7x-4 Group 2: 2x4+5x3 Pull out from each group separately :Group 1: (7x+4) • (-1)Group 2: (2x+5) • (x3)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
3.3 Find roots (zeroes) of : F(x) = 2x4+5x3-7x-4Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 2 and the Trailing Constant is -4. The factor(s) are: of the Leading Coefficient : 1,2 of the Trailing Constant : 1 ,2 ,4 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | 0.00 | x+1 |
| -1 | 2 | -0.50 | -1.00 | |
| -2 | 1 | -2.00 | 2.00 | |
| -4 | 1 | -4.00 | 216.00 | |
| 1 | 1 | 1.00 | -4.00 | |
| 1 | 2 | 0.50 | -6.75 | |
| 2 | 1 | 2.00 | 54.00 | |
| 4 | 1 | 4.00 | 800.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that 2x4+5x3-7x-4 can be divided with x+1
Polynomial Long Division :
3.4 Polynomial Long Division Dividing : 2x4+5x3-7x-4 ("Dividend") By : x+1 ("Divisor")
| dividend | 2x4 | + | 5x3 | - | 7x | - | 4 |
| - divisor | * 2x3 | 2x4 | + | 2x3 | |||
| remainder | 3x3 | - | 7x | - | 4 | ||
| - divisor | * 3x2 | 3x3 | + | 3x2 | |||
| remainder | - | 3x2 | - | 7x | - | 4 | |
| - divisor | * -3x1 | - | 3x2 | - | 3x | ||
| remainder | - | 4x | - | 4 | |||
| - divisor | * -4x0 | - | 4x | - | 4 | ||
| remainder | 0 |
Quotient : 2x3+3x2-3x-4 Remainder: 0
Polynomial Roots Calculator :
3.5 Find roots (zeroes) of : F(x) = 2x3+3x2-3x-4 See theory in step 3.3 In this case, the Leading Coefficient is 2 and the Trailing Constant is -4. The factor(s) are: of the Leading Coefficient : 1,2 of the Trailing Constant : 1 ,2 ,4 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | 0.00 | x+1 |
| -1 | 2 | -0.50 | -2.00 | |
| -2 | 1 | -2.00 | -2.00 | |
| -4 | 1 | -4.00 | -72.00 | |
| 1 | 1 | 1.00 | -2.00 | |
| 1 | 2 | 0.50 | -4.50 | |
| 2 | 1 | 2.00 | 18.00 | |
| 4 | 1 | 4.00 | 160.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that 2x3+3x2-3x-4 can be divided with x+1
Polynomial Long Division :
3.6 Polynomial Long Division Dividing : 2x3+3x2-3x-4 ("Dividend") By : x+1 ("Divisor")
| dividend | 2x3 | + | 3x2 | - | 3x | - | 4 |
| - divisor | * 2x2 | 2x3 | + | 2x2 | |||
| remainder | x2 | - | 3x | - | 4 | ||
| - divisor | * x1 | x2 | + | x | |||
| remainder | - | 4x | - | 4 | |||
| - divisor | * -4x0 | - | 4x | - | 4 | ||
| remainder | 0 |
Quotient : 2x2+x-4 Remainder: 0
Trying to factor by splitting the middle term
3.7 Factoring 2x2+x-4 The first term is, 2x2 its coefficient is 2 .The middle term is, +x its coefficient is 1 .The last term, "the constant", is -4 Step-1 : Multiply the coefficient of the first term by the constant 2 • -4 = -8 Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is 1 .
| -8 | + | 1 | = | -7 |
| -4 | + | 2 | = | -2 |
| -2 | + | 4 | = | 2 |
| -1 | + | 8 | = | 7 |
Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored
Multiplying Exponential Expressions :
3.8 Multiply (x+1) by (x+1) The rule says : To multiply exponential expressions which have the same base, add up their exponents.In our case, the common base is (x+1) and the exponents are : 1 , as (x+1) is the same number as (x+1)1 and 1 , as (x+1) is the same number as (x+1)1 The product is therefore, (x+1)(1+1) = (x+1)2
Final result :
(2x2 + x - 4) • (x + 1)2Từ khóa » G(x)=5x^3-7x+4
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