Solve Polynomiallongdivision X^3-7x^2+15x-9 Tiger Algebra Solver
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Step 1 :
Equation at the end of step 1 :
(((x3) - 7x2) + 15x) - 9Step 2 :
Checking for a perfect cube :
2.1 x3-7x2+15x-9 is not a perfect cube
Trying to factor by pulling out :
2.2 Factoring: x3-7x2+15x-9 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: 15x-9 Group 2: x3-7x2 Pull out from each group separately :Group 1: (5x-3) • (3)Group 2: (x-7) • (x2)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
2.3 Find roots (zeroes) of : F(x) = x3-7x2+15x-9Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 1 and the Trailing Constant is -9. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,3 ,9 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | -32.00 | |
| -3 | 1 | -3.00 | -144.00 | |
| -9 | 1 | -9.00 | -1440.00 | |
| 1 | 1 | 1.00 | 0.00 | x-1 |
| 3 | 1 | 3.00 | 0.00 | x-3 |
| 9 | 1 | 9.00 | 288.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that x3-7x2+15x-9 can be divided by 2 different polynomials,including by x-3
Polynomial Long Division :
2.4 Polynomial Long Division Dividing : x3-7x2+15x-9 ("Dividend") By : x-3 ("Divisor")
| dividend | x3 | - | 7x2 | + | 15x | - | 9 |
| - divisor | * x2 | x3 | - | 3x2 | |||
| remainder | - | 4x2 | + | 15x | - | 9 | |
| - divisor | * -4x1 | - | 4x2 | + | 12x | ||
| remainder | 3x | - | 9 | ||||
| - divisor | * 3x0 | 3x | - | 9 | |||
| remainder | 0 |
Quotient : x2-4x+3 Remainder: 0
Trying to factor by splitting the middle term
2.5 Factoring x2-4x+3 The first term is, x2 its coefficient is 1 .The middle term is, -4x its coefficient is -4 .The last term, "the constant", is +3 Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3 Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is -4 .
| -3 | + | -1 | = | -4 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -1 x2 - 3x - 1x - 3Step-4 : Add up the first 2 terms, pulling out like factors : x • (x-3) Add up the last 2 terms, pulling out common factors : 1 • (x-3) Step-5 : Add up the four terms of step 4 : (x-1) • (x-3) Which is the desired factorization
Multiplying Exponential Expressions :
2.6 Multiply (x-3) by (x-3) The rule says : To multiply exponential expressions which have the same base, add up their exponents.In our case, the common base is (x-3) and the exponents are : 1 , as (x-3) is the same number as (x-3)1 and 1 , as (x-3) is the same number as (x-3)1 The product is therefore, (x-3)(1+1) = (x-3)2
Final result :
(x - 1) • (x - 3)2Từ khóa » F(x)=7x+2 G(x)=15x-9
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