Solve Polynomiallongdivision X^3-7x^2+15x-9 Tiger Algebra Solver

Step 1 :

Equation at the end of step 1 :

(((x3) - 7x2) + 15x) - 9

Step 2 :

Checking for a perfect cube :

2.1 x3-7x2+15x-9 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3-7x2+15x-9 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: 15x-9 Group 2: x3-7x2 Pull out from each group separately :Group 1: (5x-3) • (3)Group 2: (x-7) • (x2)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

2.3 Find roots (zeroes) of : F(x) = x3-7x2+15x-9Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 1 and the Trailing Constant is -9. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,3 ,9 Let us test ....

PQP/QF(P/Q)Divisor
-1 1 -1.00 -32.00
-3 1 -3.00 -144.00
-9 1 -9.00 -1440.00
1 1 1.00 0.00 x-1
3 1 3.00 0.00 x-3
9 1 9.00 288.00

The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that x3-7x2+15x-9 can be divided by 2 different polynomials,including by x-3

Polynomial Long Division :

2.4 Polynomial Long Division Dividing : x3-7x2+15x-9 ("Dividend") By : x-3 ("Divisor")

dividend x3 - 7x2 + 15x - 9
- divisor * x2 x3 - 3x2
remainder- 4x2 + 15x - 9
- divisor * -4x1 - 4x2 + 12x
remainder 3x - 9
- divisor * 3x0 3x - 9
remainder0

Quotient : x2-4x+3 Remainder: 0

Trying to factor by splitting the middle term

2.5 Factoring x2-4x+3 The first term is, x2 its coefficient is 1 .The middle term is, -4x its coefficient is -4 .The last term, "the constant", is +3 Step-1 : Multiply the coefficient of the first term by the constant 13 = 3 Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is -4 .

-3 + -1 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -1 x2 - 3x - 1x - 3Step-4 : Add up the first 2 terms, pulling out like factors : x • (x-3) Add up the last 2 terms, pulling out common factors : 1 • (x-3) Step-5 : Add up the four terms of step 4 : (x-1) • (x-3) Which is the desired factorization

Multiplying Exponential Expressions :

2.6 Multiply (x-3) by (x-3) The rule says : To multiply exponential expressions which have the same base, add up their exponents.In our case, the common base is (x-3) and the exponents are : 1 , as (x-3) is the same number as (x-3)1 and 1 , as (x-3) is the same number as (x-3)1 The product is therefore, (x-3)(1+1) = (x-3)2

Final result :

(x - 1) • (x - 3)2

Từ khóa » F(x)=7x+2 G(x)=15x-9