Solve Polynomialrootcalculator 2x^3-3x^2-29x-30 Tiger Algebra ...
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Step 1 :
Equation at the end of step 1 :
(((2 • (x3)) - 3x2) - 29x) - 30Step 2 :
Equation at the end of step 2 :
((2x3 - 3x2) - 29x) - 30Step 3 :
Checking for a perfect cube :
3.1 2x3-3x2-29x-30 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 2x3-3x2-29x-30 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: -29x-30 Group 2: 2x3-3x2 Pull out from each group separately :Group 1: (29x+30) • (-1)Group 2: (2x-3) • (x2)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
3.3 Find roots (zeroes) of : F(x) = 2x3-3x2-29x-30Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 2 and the Trailing Constant is -30. The factor(s) are: of the Leading Coefficient : 1,2 of the Trailing Constant : 1 ,2 ,3 ,5 ,6 ,10 ,15 ,30 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | -6.00 | |
| -1 | 2 | -0.50 | -16.50 | |
| -2 | 1 | -2.00 | 0.00 | x+2 |
| -3 | 1 | -3.00 | -24.00 | |
| -3 | 2 | -1.50 | 0.00 | 2x+3 |
| -5 | 1 | -5.00 | -210.00 | |
| -5 | 2 | -2.50 | -7.50 | |
| -6 | 1 | -6.00 | -396.00 | |
| -10 | 1 | -10.00 | -2040.00 | |
| -15 | 1 | -15.00 | -7020.00 | |
| -15 | 2 | -7.50 | -825.00 | |
| -30 | 1 | -30.00 | -55860.00 | |
| 1 | 1 | 1.00 | -60.00 | |
| 1 | 2 | 0.50 | -45.00 | |
| 2 | 1 | 2.00 | -84.00 | |
| 3 | 1 | 3.00 | -90.00 | |
| 3 | 2 | 1.50 | -73.50 | |
| 5 | 1 | 5.00 | 0.00 | x-5 |
| 5 | 2 | 2.50 | -90.00 | |
| 6 | 1 | 6.00 | 120.00 | |
| 10 | 1 | 10.00 | 1380.00 | |
| 15 | 1 | 15.00 | 5610.00 | |
| 15 | 2 | 7.50 | 427.50 | |
| 30 | 1 | 30.00 | 50400.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that 2x3-3x2-29x-30 can be divided by 3 different polynomials,including by x-5
Polynomial Long Division :
3.4 Polynomial Long Division Dividing : 2x3-3x2-29x-30 ("Dividend") By : x-5 ("Divisor")
| dividend | 2x3 | - | 3x2 | - | 29x | - | 30 |
| - divisor | * 2x2 | 2x3 | - | 10x2 | |||
| remainder | 7x2 | - | 29x | - | 30 | ||
| - divisor | * 7x1 | 7x2 | - | 35x | |||
| remainder | 6x | - | 30 | ||||
| - divisor | * 6x0 | 6x | - | 30 | |||
| remainder | 0 |
Quotient : 2x2+7x+6 Remainder: 0
Trying to factor by splitting the middle term
3.5 Factoring 2x2+7x+6 The first term is, 2x2 its coefficient is 2 .The middle term is, +7x its coefficient is 7 .The last term, "the constant", is +6 Step-1 : Multiply the coefficient of the first term by the constant 2 • 6 = 12 Step-2 : Find two factors of 12 whose sum equals the coefficient of the middle term, which is 7 .
| -12 | + | -1 | = | -13 | |
| -6 | + | -2 | = | -8 | |
| -4 | + | -3 | = | -7 | |
| -3 | + | -4 | = | -7 | |
| -2 | + | -6 | = | -8 | |
| -1 | + | -12 | = | -13 | |
| 1 | + | 12 | = | 13 | |
| 2 | + | 6 | = | 8 | |
| 3 | + | 4 | = | 7 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 4 2x2 + 3x + 4x + 6Step-4 : Add up the first 2 terms, pulling out like factors : x • (2x+3) Add up the last 2 terms, pulling out common factors : 2 • (2x+3) Step-5 : Add up the four terms of step 4 : (x+2) • (2x+3) Which is the desired factorization
Final result :
(2x + 3) • (x + 2) • (x - 5)Từ khóa » G(x)=2x^3-3x^2-29x-30
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