Solve Polynomialrootcalculator (-2x^6+5x^5-3x^4-6x^3+12x^2+5x-3)
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Step 6 :
-2x6 + 5x5 - 3x4 - 6x3 + 12x2 + 5x - 3 Simplify —————————————————————————————————————— -x3 + x2 - x - 3Step 7 :
Pulling out like terms :
7.1 Pull out like factors : -2x6 + 5x5 - 3x4 - 6x3 + 12x2 + 5x - 3 = -1 • (2x6 - 5x5 + 3x4 + 6x3 - 12x2 - 5x + 3)
Step 8 :
Pulling out like terms :
8.1 Pull out like factors : -x3 + x2 - x - 3 = -1 • (x3 - x2 + x + 3)
Checking for a perfect cube :
8.2 x3 - x2 + x + 3 is not a perfect cube
Trying to factor by pulling out :
8.3 Factoring: x3 - x2 + x + 3 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: x + 3 Group 2: x3 - x2 Pull out from each group separately :Group 1: (x + 3) • (1)Group 2: (x - 1) • (x2)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
8.4 Find roots (zeroes) of : F(x) = 2x6 - 5x5 + 3x4 + 6x3 - 12x2 - 5x + 3Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 2 and the Trailing Constant is 3. The factor(s) are: of the Leading Coefficient : 1,2 of the Trailing Constant : 1 ,3 Let us test ....
P | Q | P/Q | F(P/Q) | Divisor |
---|---|---|---|---|
-1 | 1 | -1.00 | 0.00 | x + 1 |
-1 | 2 | -0.50 | 2.12 | |
-3 | 1 | -3.00 | 2664.00 | |
-3 | 2 | -1.50 | 39.19 | |
1 | 1 | 1.00 | -8.00 | |
1 | 2 | 0.50 | -1.69 | |
3 | 1 | 3.00 | 528.00 | |
3 | 2 | 1.50 | -11.25 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that 2x6 - 5x5 + 3x4 + 6x3 - 12x2 - 5x + 3 can be divided with x + 1
Polynomial Long Division :
8.5 Polynomial Long Division Dividing : 2x6 - 5x5 + 3x4 + 6x3 - 12x2 - 5x + 3 ("Dividend") By : x + 1 ("Divisor")
dividend | 2x6 | - | 5x5 | + | 3x4 | + | 6x3 | - | 12x2 | - | 5x | + | 3 |
- divisor | * 2x5 | 2x6 | + | 2x5 | |||||||||
remainder | - | 7x5 | + | 3x4 | + | 6x3 | - | 12x2 | - | 5x | + | 3 | |
- divisor | * -7x4 | - | 7x5 | - | 7x4 | ||||||||
remainder | 10x4 | + | 6x3 | - | 12x2 | - | 5x | + | 3 | ||||
- divisor | * 10x3 | 10x4 | + | 10x3 | |||||||||
remainder | - | 4x3 | - | 12x2 | - | 5x | + | 3 | |||||
- divisor | * -4x2 | - | 4x3 | - | 4x2 | ||||||||
remainder | - | 8x2 | - | 5x | + | 3 | |||||||
- divisor | * -8x1 | - | 8x2 | - | 8x | ||||||||
remainder | 3x | + | 3 | ||||||||||
- divisor | * 3x0 | 3x | + | 3 | |||||||||
remainder | 0 |
Quotient : 2x5-7x4+10x3-4x2-8x+3 Remainder: 0
Polynomial Roots Calculator :
8.6 Find roots (zeroes) of : F(x) = 2x5-7x4+10x3-4x2-8x+3 See theory in step 8.4 In this case, the Leading Coefficient is 2 and the Trailing Constant is 3. The factor(s) are: of the Leading Coefficient : 1,2 of the Trailing Constant : 1 ,3 Let us test ....
P | Q | P/Q | F(P/Q) | Divisor |
---|---|---|---|---|
-1 | 1 | -1.00 | -12.00 | |
-1 | 2 | -0.50 | 4.25 | |
-3 | 1 | -3.00 | -1332.00 | |
-3 | 2 | -1.50 | -78.38 | |
1 | 1 | 1.00 | -4.00 | |
1 | 2 | 0.50 | -1.12 | |
3 | 1 | 3.00 | 132.00 | |
3 | 2 | 1.50 | -4.50 |
Polynomial Roots Calculator found no rational roots
Polynomial Roots Calculator :
8.7 Find roots (zeroes) of : F(x) = x3-x2+x+3 See theory in step 8.4 In this case, the Leading Coefficient is 1 and the Trailing Constant is 3. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,3 Let us test ....
P | Q | P/Q | F(P/Q) | Divisor |
---|---|---|---|---|
-1 | 1 | -1.00 | 0.00 | x+1 |
-3 | 1 | -3.00 | -36.00 | |
1 | 1 | 1.00 | 4.00 | |
3 | 1 | 3.00 | 24.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that x3-x2+x+3 can be divided with x+1
Polynomial Long Division :
8.8 Polynomial Long Division Dividing : x3-x2+x+3 ("Dividend") By : x+1 ("Divisor")
dividend | x3 | - | x2 | + | x | + | 3 |
- divisor | * x2 | x3 | + | x2 | |||
remainder | - | 2x2 | + | x | + | 3 | |
- divisor | * -2x1 | - | 2x2 | - | 2x | ||
remainder | 3x | + | 3 | ||||
- divisor | * 3x0 | 3x | + | 3 | |||
remainder | 0 |
Quotient : x2-2x+3 Remainder: 0
Trying to factor by splitting the middle term
8.9 Factoring x2-2x+3 The first term is, x2 its coefficient is 1 .The middle term is, -2x its coefficient is -2 .The last term, "the constant", is +3 Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3 Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is -2 .
-3 | + | -1 | = | -4 |
-1 | + | -3 | = | -4 |
1 | + | 3 | = | 4 |
3 | + | 1 | = | 4 |
Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored
Canceling Out :
8.10 Cancel out (x+1) which appears on both sides of the fraction line.
Step 9 :
Pulling out like terms :
9.1 Pull out like factors : -x2 + 2x - 3 = -1 • (x2 - 2x + 3)
Polynomial Roots Calculator :
9.2 Find roots (zeroes) of : F(x) = -2x5 + 7x4 - 10x3 + 4x2 + 8x - 3 See theory in step 8.4 In this case, the Leading Coefficient is -2 and the Trailing Constant is -3. The factor(s) are: of the Leading Coefficient : 1,2 of the Trailing Constant : 1 ,3 Let us test ....
P | Q | P/Q | F(P/Q) | Divisor |
---|---|---|---|---|
-1 | 1 | -1.00 | 12.00 | |
-1 | 2 | -0.50 | -4.25 | |
-3 | 1 | -3.00 | 1332.00 | |
-3 | 2 | -1.50 | 78.38 | |
1 | 1 | 1.00 | 4.00 | |
1 | 2 | 0.50 | 1.12 | |
3 | 1 | 3.00 | -132.00 | |
3 | 2 | 1.50 | 4.50 |
Polynomial Roots Calculator found no rational roots
Final result :
-2x5 + 7x4 - 10x3 + 4x2 + 8x - 3 ———————————————————————————————— -x2 + 2x - 3Từ khóa » F(x)=2x^3+6x^2-5x-3 G(x)=3x-4
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