Solve Polynomialrootcalculator (4x^5-3x^3+2x^2-7) - Tiger Algebra
Step 1 :
Equation at the end of step 1 :
((((4•(x5))-(3•(x3)))+(2•(x2)))-7)-((((x4)+2x3)-4x)-3)Step 2 :
Equation at the end of step 2 :
((((4•(x5))-(3•(x3)))+2x2)-7)-(x4+2x3-4x-3)Step 3 :
Equation at the end of step 3 :
((((4•(x5))-3x3)+2x2)-7)-(x4+2x3-4x-3)Step 4 :
Equation at the end of step 4 :
(((22x5 - 3x3) + 2x2) - 7) - (x4 + 2x3 - 4x - 3)Step 5 :
Trying to factor by pulling out :
5.1 Factoring: 4x5-x4-5x3+2x2+4x-4 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: 2x2-5x3 Group 2: 4x5-x4 Group 3: 4x-4 Pull out from each group separately :Group 1: (5x-2) • (-x2)Group 2: (4x-1) • (x4)Group 3: (x-1) • (4) Looking for common sub-expressions : Group 1: (5x-2) • (-x2) Group 3: (x-1) • (4) Group 2: (4x-1) • (x4)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
5.2 Find roots (zeroes) of : F(x) = 4x5-x4-5x3+2x2+4x-4Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 4 and the Trailing Constant is -4. The factor(s) are: of the Leading Coefficient : 1,2 ,4 of the Trailing Constant : 1 ,2 ,4 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | -6.00 | |
| -1 | 2 | -0.50 | -5.06 | |
| -1 | 4 | -0.25 | -4.80 | |
| -2 | 1 | -2.00 | -108.00 | |
| -4 | 1 | -4.00 | -4020.00 | |
| 1 | 1 | 1.00 | 0.00 | x-1 |
| 1 | 2 | 0.50 | -2.06 | |
| 1 | 4 | 0.25 | -2.95 | |
| 2 | 1 | 2.00 | 84.00 | |
| 4 | 1 | 4.00 | 3564.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that 4x5-x4-5x3+2x2+4x-4 can be divided with x-1
Polynomial Long Division :
5.3 Polynomial Long Division Dividing : 4x5-x4-5x3+2x2+4x-4 ("Dividend") By : x-1 ("Divisor")
| dividend | 4x5 | - | x4 | - | 5x3 | + | 2x2 | + | 4x | - | 4 |
| - divisor | * 4x4 | 4x5 | - | 4x4 | |||||||
| remainder | 3x4 | - | 5x3 | + | 2x2 | + | 4x | - | 4 | ||
| - divisor | * 3x3 | 3x4 | - | 3x3 | |||||||
| remainder | - | 2x3 | + | 2x2 | + | 4x | - | 4 | |||
| - divisor | * -2x2 | - | 2x3 | + | 2x2 | ||||||
| remainder | 4x | - | 4 | ||||||||
| - divisor | * 0x1 | ||||||||||
| remainder | 4x | - | 4 | ||||||||
| - divisor | * 4x0 | 4x | - | 4 | |||||||
| remainder | 0 |
Quotient : 4x4+3x3-2x2+4 Remainder: 0
Polynomial Roots Calculator :
5.4 Find roots (zeroes) of : F(x) = 4x4+3x3-2x2+4 See theory in step 5.2 In this case, the Leading Coefficient is 4 and the Trailing Constant is 4. The factor(s) are: of the Leading Coefficient : 1,2 ,4 of the Trailing Constant : 1 ,2 ,4 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | 3.00 | |
| -1 | 2 | -0.50 | 3.38 | |
| -1 | 4 | -0.25 | 3.84 | |
| -2 | 1 | -2.00 | 36.00 | |
| -4 | 1 | -4.00 | 804.00 | |
| 1 | 1 | 1.00 | 9.00 | |
| 1 | 2 | 0.50 | 4.12 | |
| 1 | 4 | 0.25 | 3.94 | |
| 2 | 1 | 2.00 | 84.00 | |
| 4 | 1 | 4.00 | 1188.00 |
Polynomial Roots Calculator found no rational roots
Final result :
(4x4 + 3x3 - 2x2 + 4) • (x - 1)Từ khóa » G(x)=4x^5-3x^6+2x^3-1
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