Solve Polynomialrootcalculator X^3-5x^2-17x+21 Tiger Algebra Solver
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Step 1 :
Equation at the end of step 1 :
(((x3) - 5x2) - 17x) + 21Step 2 :
Checking for a perfect cube :
2.1 x3-5x2-17x+21 is not a perfect cube
Trying to factor by pulling out :
2.2 Factoring: x3-5x2-17x+21 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: -17x+21 Group 2: x3-5x2 Pull out from each group separately :Group 1: (-17x+21) • (1) = (17x-21) • (-1)Group 2: (x-5) • (x2)Bad news !! Factoring by pulling out fails : The groups have no common factor and can not be added up to form a multiplication.
Polynomial Roots Calculator :
2.3 Find roots (zeroes) of : F(x) = x3-5x2-17x+21Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 1 and the Trailing Constant is 21. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,3 ,7 ,21 Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor |
|---|---|---|---|---|
| -1 | 1 | -1.00 | 32.00 | |
| -3 | 1 | -3.00 | 0.00 | x+3 |
| -7 | 1 | -7.00 | -448.00 | |
| -21 | 1 | -21.00 | -11088.00 | |
| 1 | 1 | 1.00 | 0.00 | x-1 |
| 3 | 1 | 3.00 | -48.00 | |
| 7 | 1 | 7.00 | 0.00 | x-7 |
| 21 | 1 | 21.00 | 6720.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms In our case this means that x3-5x2-17x+21 can be divided by 3 different polynomials,including by x-7
Polynomial Long Division :
2.4 Polynomial Long Division Dividing : x3-5x2-17x+21 ("Dividend") By : x-7 ("Divisor")
| dividend | x3 | - | 5x2 | - | 17x | + | 21 |
| - divisor | * x2 | x3 | - | 7x2 | |||
| remainder | 2x2 | - | 17x | + | 21 | ||
| - divisor | * 2x1 | 2x2 | - | 14x | |||
| remainder | - | 3x | + | 21 | |||
| - divisor | * -3x0 | - | 3x | + | 21 | ||
| remainder | 0 |
Quotient : x2+2x-3 Remainder: 0
Trying to factor by splitting the middle term
2.5 Factoring x2+2x-3 The first term is, x2 its coefficient is 1 .The middle term is, +2x its coefficient is 2 .The last term, "the constant", is -3 Step-1 : Multiply the coefficient of the first term by the constant 1 • -3 = -3 Step-2 : Find two factors of -3 whose sum equals the coefficient of the middle term, which is 2 .
| -3 | + | 1 | = | -2 | |
| -1 | + | 3 | = | 2 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and 3 x2 - 1x + 3x - 3Step-4 : Add up the first 2 terms, pulling out like factors : x • (x-1) Add up the last 2 terms, pulling out common factors : 3 • (x-1) Step-5 : Add up the four terms of step 4 : (x+3) • (x-1) Which is the desired factorization
Final result :
(x + 3) • (x - 1) • (x - 7)Từ khóa » G(x)=x^3+5x^2-17x-21
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[PDF] ASSET_2_Solutions.pdf