Solve Quadraticequations C^2+6c+9=0 Tiger Algebra Solver

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring c2+6c+9 The first term is, c2 its coefficient is 1 .The middle term is, +6c its coefficient is 6 .The last term, "the constant", is +9 Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9 Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is 6 .

-9	+	-1	=	-10
-3	+	-3	=	-6
-1	+	-9	=	-10
1	+	9	=	10
3	+	3	=	6	That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 3 c2 + 3c + 3c + 9Step-4 : Add up the first 2 terms, pulling out like factors : c • (c+3) Add up the last 2 terms, pulling out common factors : 3 • (c+3) Step-5 : Add up the four terms of step 4 : (c+3) • (c+3) Which is the desired factorization

Multiplying Exponential Expressions :

1.2 Multiply (c+3) by (c+3) The rule says : To multiply exponential expressions which have the same base, add up their exponents.In our case, the common base is (c+3) and the exponents are : 1 , as (c+3) is the same number as (c+3)1 and 1 , as (c+3) is the same number as (c+3)1 The product is therefore, (c+3)(1+1) = (c+3)2

Equation at the end of step 1 :

(c + 3)2 = 0

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : (c+3)2 = 0 (c+3) 2 represents, in effect, a product of 2 terms which is equal to zero For the product to be zero, at least one of these terms must be zero. Since all these terms are equal to each other, it actually means : c+3 = 0 Subtract 3 from both sides of the equation : c = -3

Supplement : Solving Quadratic Equation Directly

Solving c2+6c+9 = 0 directly

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex :

3.1 Find the Vertex of y = c2+6c+9Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero).Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.For any parabola,Ac2+Bc+C,the c -coordinate of the vertex is given by -B/(2A) . In our case the c coordinate is -3.0000 Plugging into the parabola formula -3.0000 for c we can calculate the y -coordinate : y = 1.0 * -3.00 * -3.00 + 6.0 * -3.00 + 9.0 or y = 0.000

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = c2+6c+9 Vertex at {c,y} = {-3.00, 0.00} c-Intercept (Root) : One Root at {c,y}={-3.00, 0.00} Note that the root coincides with the Vertex and the Axis of Symmetry coinsides with the line c = 0

Solve Quadratic Equation by Completing The Square

3.2 Solving c2+6c+9 = 0 by Completing The Square . Subtract 9 from both side of the equation : c2+6c = -9Now the clever bit: Take the coefficient of c , which is 6 , divide by two, giving 3 , and finally square it giving 9 Add 9 to both sides of the equation : On the right hand side we have : -9 + 9 or, (-9/1)+(9/1) The common denominator of the two fractions is 1 Adding (-9/1)+(9/1) gives 0/1 So adding to both sides we finally get : c2+6c+9 = 0Adding 9 has completed the left hand side into a perfect square : c2+6c+9 = (c+3) • (c+3) = (c+3)2 Things which are equal to the same thing are also equal to one another. Since c2+6c+9 = 0 and c2+6c+9 = (c+3)2 then, according to the law of transitivity, (c+3)2 = 0We'll refer to this Equation as Eq. #3.2.1 The Square Root Principle says that When two things are equal, their square roots are equal.Note that the square root of (c+3)2 is (c+3)2/2 = (c+3)1 = c+3Now, applying the Square Root Principle to Eq. #3.2.1 we get: c+3 = √ 0 Subtract 3 from both sides to obtain: c = -3 + √ 0 The square root of zero is zero This quadratic equation has one solution only. That's because adding zero is the same as subtracting zero.The solution is: c = -3

Solve Quadratic Equation using the Quadratic Formula

3.3 Solving c2+6c+9 = 0 by the Quadratic Formula . According to the Quadratic Formula, c , the solution for Ac2+Bc+C = 0 , where A, B and C are numbers, often called coefficients, is given by : - B ± √ B2-4AC c = ———————— 2A In our case, A = 1 B = 6 C = 9 Accordingly, B2 - 4AC = 36 - 36 = 0Applying the quadratic formula : -6 ± √ 0 c = ————— 2The square root of zero is zero This quadratic equation has one solution only. That's because adding zero is the same as subtracting zero.The solution is: c = -6 / 2 = -3

One solution was found :

c = -3