Solve Reducingfractionstolowestterms C-5/c2-25 Tiger Algebra Solver
Reformatting the input :
Changes made to your input should not affect the solution: (1): "c2" was replaced by "c^2".
Step 1 :
5 Simplify —— c2Equation at the end of step 1 :
5 (c - ——) - 25 c2Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a fraction from a whole Rewrite the whole as a fraction using c2 as the denominator :
c c • c2 c = — = —————— 1 c2Equivalent fraction : The fraction thus generated looks different but has the same value as the whole Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions Add the two equivalent fractions which now have a common denominatorCombine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
c • c2 - (5) c3 - 5 ———————————— = —————— c2 c2Equation at the end of step 2 :
(c3 - 5) ———————— - 25 c2Step 3 :
Rewriting the whole as an Equivalent Fraction :
3.1 Subtracting a whole from a fraction Rewrite the whole as a fraction using c2 as the denominator :
25 25 • c2 25 = —— = ——————— 1 c2Trying to factor as a Difference of Cubes:
3.2 Factoring: c3 - 5 Theory : A difference of two perfect cubes, a3 - b3 can be factored into (a-b) • (a2 +ab +b2)Proof : (a-b)•(a2+ab+b2) = a3+a2b+ab2-ba2-b2a-b3 = a3+(a2b-ba2)+(ab2-b2a)-b3 = a3+0+0-b3 = a3-b3Check : 5 is not a cube !! Ruling : Binomial can not be factored as the difference of two perfect cubes
Polynomial Roots Calculator :
3.3 Find roots (zeroes) of : F(c) = c3 - 5Polynomial Roots Calculator is a set of methods aimed at finding values of c for which F(c)=0 Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers c which can be expressed as the quotient of two integersThe Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading CoefficientIn this case, the Leading Coefficient is 1 and the Trailing Constant is -5. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,5 Let us test ....
P | Q | P/Q | F(P/Q) | Divisor |
---|---|---|---|---|
-1 | 1 | -1.00 | -6.00 | |
-5 | 1 | -5.00 | -130.00 | |
1 | 1 | 1.00 | -4.00 | |
5 | 1 | 5.00 | 120.00 |
Polynomial Roots Calculator found no rational roots
Adding fractions that have a common denominator :
3.4 Adding up the two equivalent fractions
(c3-5) - (25 • c2) c3 - 25c2 - 5 —————————————————— = ————————————— c2 c2Polynomial Roots Calculator :
3.5 Find roots (zeroes) of : F(c) = c3 - 25c2 - 5 See theory in step 3.3 In this case, the Leading Coefficient is 1 and the Trailing Constant is -5. The factor(s) are: of the Leading Coefficient : 1 of the Trailing Constant : 1 ,5 Let us test ....
P | Q | P/Q | F(P/Q) | Divisor |
---|---|---|---|---|
-1 | 1 | -1.00 | -31.00 | |
-5 | 1 | -5.00 | -755.00 | |
1 | 1 | 1.00 | -29.00 | |
5 | 1 | 5.00 | -505.00 |
Polynomial Roots Calculator found no rational roots
Final result :
c3 25c2 - 5 ————————————— c2Từ khóa » C2+25/c2-25 - C/c+5
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