Solve Simplificationorothersimpleresults C2-8c+16 Tiger Algebra ...
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Other Ways to Solve
Simplification or other simple resultsStep by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution: (1): "c2" was replaced by "c^2".
Step 1 :
Trying to factor by splitting the middle term
1.1 Factoring c2-8c+16 The first term is, c2 its coefficient is 1 .The middle term is, -8c its coefficient is -8 .The last term, "the constant", is +16 Step-1 : Multiply the coefficient of the first term by the constant 1 • 16 = 16 Step-2 : Find two factors of 16 whose sum equals the coefficient of the middle term, which is -8 .
| -16 | + | -1 | = | -17 | |
| -8 | + | -2 | = | -10 | |
| -4 | + | -4 | = | -8 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and -4 c2 - 4c - 4c - 16Step-4 : Add up the first 2 terms, pulling out like factors : c • (c-4) Add up the last 2 terms, pulling out common factors : 4 • (c-4) Step-5 : Add up the four terms of step 4 : (c-4) • (c-4) Which is the desired factorization
Multiplying Exponential Expressions :
1.2 Multiply (c-4) by (c-4) The rule says : To multiply exponential expressions which have the same base, add up their exponents.In our case, the common base is (c-4) and the exponents are : 1 , as (c-4) is the same number as (c-4)1 and 1 , as (c-4) is the same number as (c-4)1 The product is therefore, (c-4)(1+1) = (c-4)2
Final result :
(c - 4)2How did we do?
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