Solve Simplificationorothersimpleresults X^3+4x^2-7x-28 Tiger ...

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Camera Icon Enter an equation or problemClear Camera Icon Solve Camera input is not recognized!Keyboardarrow leftarrow rightenterdelsquare 2square 10axy/|abs|( )789*fractionsqrt root456-root%123+<>0,.=abcabcdefghijklmnopqrstuvwxyz␣.Solution - Simplification or other simple results (x2−7)⋅(x+4) (x^2-7)*(x+4)

Other Ways to Solve

Simplification or other simple results

Step by Step Solution

Step 1 :

Equation at the end of step 1 :

(((x3) + 22x2) - 7x) - 28

Step 2 :

Checking for a perfect cube :

2.1 x3+4x2-7x-28 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3+4x2-7x-28 Thoughtfully split the expression at hand into groups, each group having two terms :Group 1: -7x-28 Group 2: 4x2+x3 Pull out from each group separately :Group 1: (x+4) • (-7)Group 2: (x+4) • (x2) -------------------Add up the two groups : (x+4) • (x2-7) Which is the desired factorization

Trying to factor as a Difference of Squares :

2.3 Factoring: x2-7 Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)Proof : (A+B) • (A-B) = A2 - AB + BA - B2 = A2 - AB + AB - B2 = A2 - B2Note : AB = BA is the commutative property of multiplication. Note : - AB + AB equals zero and is therefore eliminated from the expression.Check : 7 is not a square !! Ruling : Binomial can not be factored as the difference of two perfect squares.

Final result :

(x2 - 7) • (x + 4)

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