SOLVED:9. C6H5COOH(aq) → C6H5COO- (aq) + H+ ... - Numerade

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9. C6H5COOH(aq) → C6H5COO- (aq) + H+ (aq) has a Ka = 2.50 x 10^-6. If the following are present in 3.0 L of an aqueous solution, is the system at equilibrium? If not, which way will it shift? 1.50 moles C6H5COOH, 1.5 moles C6H5COO-, pH = 2.35. 9. C6H5COOH(aq) → C6H5COO- (aq) + H+ (aq) has a Ka = 2.50 x 10^-6. If the following are present in 3.0 L of an aqueous solution, is the system at equilibrium? If not, which way will it shift? 1.50 moles C6H5COOH, 1.5 moles C6H5COO-, pH = 2.35. Show more…

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Chemistry: Structure and Properties Nivaldo Tro 2nd Edition

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Calculate the initial concentration of C6H5COOH and C6H5COO-: Initial concentration of C6H5COOH = 1.50 moles / 3.0 L = 0.50 M Initial concentration of C6H5COO- = 1.5 moles / 3.0 L = 0.50 M Show more…

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Submit Thanks for your feedback! 9. C6H5COOH(aq) → C6H5COO- (aq) + H+ (aq) has a Ka = 2.50 x 10^-6. If the following are present in 3.0 L of an aqueous solution, is the system at equilibrium? If not, which way will it shift? 1.50 moles C6H5COOH, 1.5 moles C6H5COO-, pH = 2.35. Play audio Feedback Powered by NumerAI

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