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C7H16 + O2 -> CO2 + H2O Answer the following question. Determine the volume of carbon dioxide produced when 836 g heptane is completely consumed at STP. C7H16 + O2 -> CO2 + H2O Answer the following question. Determine the volume of carbon dioxide produced when 836 g heptane is completely consumed at STP.Added by David C.
Step 1
Given mass of heptane = 836 g Molar mass of heptane (C7H16) = 7(12.01) + 16(1.01) = 100.19 g/mol Moles of heptane = 836 g / 100.19 g/mol = 8.34 moles Show more…
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