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If you have the balanced formula C2H8 + 5 O2 - 3CO2 + 4 H2O, and your perform this reaction and receive 125. moles of water, how many moles of carbon dioxide should you have?

then using the same equation C2H8 + 5 O2 - 3CO2 + 4 H2O. You supply oxygen to this reaction. The oxygen is 2.31 kg of O2. How many grams of C2H8 is needed to react with?

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03/27/21

1 Expert Answer

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Hello, John,

I will answer the questions based on the assumption you meant to write C3H8, not C2H8 (no such molecule that I'm aware of). The equation isn't balanced for the C2H8, but it works for C3H8.

C3H8 + 5 O2 - 3CO2 + 4 H2O

The first question: To find how many moles of CO2 we should have if 125 moles of water were produced, the equation tells us the molar ratio between water and CO2:

(4 moles H2O)/(3 moles CO2)

To find the moles CO2:

(3 moles CO2)/(4 moles H2O)* (125 moles H2O) = 93.75moles CO2

===

Next we are asked how much C3H8 do we need for 2.31 kg of O2. Convert 2.31kg into grams and then divide that by oxygen's molar mass to find the moles O2 present (72.2 moles). Find the molar ratio of the two compounds:

(1 moles C3H8)/( 5 moles O2)

(1 moles C3H8)/( 5 moles O2)*(72.2 moles O2) = 14.4 moles C3H8

Bob

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