Table Of Cell Areas For H3 Resolutions
Cell counts
We list the number of hexagons and pentagons at each H3 resolution. There are always exactly 1212 pentagons at every resolution.
| Res | Total number of cells | Number of hexagons | Number of pentagons |
|---|---|---|---|
| 0 | 122 | 110 | 12 |
| 1 | 842 | 830 | 12 |
| 2 | 5,882 | 5,870 | 12 |
| 3 | 41,162 | 41,150 | 12 |
| 4 | 288,122 | 288,110 | 12 |
| 5 | 2,016,842 | 2,016,830 | 12 |
| 6 | 14,117,882 | 14,117,870 | 12 |
| 7 | 98,825,162 | 98,825,150 | 12 |
| 8 | 691,776,122 | 691,776,110 | 12 |
| 9 | 4,842,432,842 | 4,842,432,830 | 12 |
| 10 | 33,897,029,882 | 33,897,029,870 | 12 |
| 11 | 237,279,209,162 | 237,279,209,150 | 12 |
| 12 | 1,660,954,464,122 | 1,660,954,464,110 | 12 |
| 13 | 11,626,681,248,842 | 11,626,681,248,830 | 12 |
| 14 | 81,386,768,741,882 | 81,386,768,741,870 | 12 |
| 15 | 569,707,381,193,162 | 569,707,381,193,150 | 12 |
Cell areas
cautionCell areas are computed with a spherical model of the earth using the authalic radius given by WGS84/EPSG:4326.
Average area in km2
The area of an H3 cell varies based on its position relative to the icosahedron vertices. We show the average hexagon areas for each resolution. All pentagons within a resolution have the same area.
| Res | Average Hexagon Area (km2) | Pentagon Area* (km2) | Ratio (P/H) |
|---|---|---|---|
| 0 | 4,357,449.416078381 | 2,562,182.162955496 | 0.5880 |
| 1 | 609,788.441794133 | 328,434.586246469 | 0.5386 |
| 2 | 86,801.780398997 | 44,930.898497879 | 0.5176 |
| 3 | 12,393.434655088 | 6,315.472267516 | 0.5096 |
| 4 | 1,770.347654491 | 896.582383141 | 0.5064 |
| 5 | 252.903858182 | 127.785583023 | 0.5053 |
| 6 | 36.129062164 | 18.238749548 | 0.5048 |
| 7 | 5.161293360 | 2.604669397 | 0.5047 |
| 8 | 0.737327598 | 0.372048038 | 0.5046 |
| 9 | 0.105332513 | 0.053147195 | 0.5046 |
| 10 | 0.015047502 | 0.007592318 | 0.5046 |
| 11 | 0.002149643 | 0.001084609 | 0.5046 |
| 12 | 0.000307092 | 0.000154944 | 0.5046 |
| 13 | 0.000043870 | 0.000022135 | 0.5046 |
| 14 | 0.000006267 | 0.000003162 | 0.5046 |
| 15 | 0.000000895 | 0.000000452 | 0.5046 |
*: Within a given resolution, all pentagons have the same area.
Average area in m2
Here are the same areas, but in m2.
| Res | Average Hexagon Area (m2) | Pentagon Area* (m2) |
|---|---|---|
| 0 | 4,357,449,416,078.392 | 2,562,182,162,955.496 |
| 1 | 609,788,441,794.134 | 328,434,586,246.469 |
| 2 | 86,801,780,398.997 | 44,930,898,497.879 |
| 3 | 12,393,434,655.088 | 6,315,472,267.516 |
| 4 | 1,770,347,654.491 | 896,582,383.141 |
| 5 | 252,903,858.182 | 127,785,583.023 |
| 6 | 36,129,062.164 | 18,238,749.548 |
| 7 | 5,161,293.360 | 2,604,669.397 |
| 8 | 737,327.598 | 372,048.038 |
| 9 | 105,332.513 | 53,147.195 |
| 10 | 15,047.502 | 7,592.318 |
| 11 | 2,149.643 | 1,084.609 |
| 12 | 307.092 | 154.944 |
| 13 | 43.870 | 22.135 |
| 14 | 6.267 | 3.162 |
| 15 | 0.895 | 0.452 |
*: Within a given resolution, all pentagons have the same area.
Hexagon min and max areas
The area of an H3 cell varies based on its position relative to the icosahedron vertices. We compute the minimum and maximum values for the hexagon areas (excluding the pentagons) at each resolution, and show their ratio.
| Res | Min Hexagon Area (km^2) | Max Hexagon Area (km^2) | Ratio (max/min) |
|---|---|---|---|
| 0 | 4,106,166.334463915 | 4,977,807.027442012 | 1.212276 |
| 1 | 447,684.201817940 | 729,486.875275344 | 1.629468 |
| 2 | 56,786.622889474 | 104,599.807218925 | 1.841980 |
| 3 | 7,725.505769639 | 14,950.773301379 | 1.935248 |
| 4 | 1,084.005635363 | 2,135.986983965 | 1.970457 |
| 5 | 153.766244448 | 305.144308779 | 1.984469 |
| 6 | 21.910021013 | 43.592111685 | 1.989597 |
| 7 | 3.126836030 | 6.227445905 | 1.991613 |
| 8 | 0.446526174 | 0.889635157 | 1.992347 |
| 9 | 0.063780227 | 0.127090737 | 1.992635 |
| 10 | 0.009110981 | 0.018155820 | 1.992740 |
| 11 | 0.001301542 | 0.002593689 | 1.992782 |
| 12 | 0.000185933 | 0.000370527 | 1.992797 |
| 13 | 0.000026562 | 0.000052932 | 1.992802 |
| 14 | 0.000003795 | 0.000007562 | 1.992805 |
| 15 | 0.000000542 | 0.000001080 | 1.992805 |
Edge lengths
cautionEdge lengths are computed with a spherical model of the earth using the authalic radius given by WGS84/EPSG:4326. Average edge lengths were calculated exactly for resolutions 0 through 6 and extrapolated for finer resolutions.
| Res | Average edge length (Km) |
|---|---|
| 0 | 1281.256011 |
| 1 | 483.0568391 |
| 2 | 182.5129565 |
| 3 | 68.97922179 |
| 4 | 26.07175968 |
| 5 | 9.854090990 |
| 6 | 3.724532667 |
| 7 | 1.406475763 |
| 8 | 0.531414010 |
| 9 | 0.200786148 |
| 10 | 0.075863783 |
| 11 | 0.028663897 |
| 12 | 0.010830188 |
| 13 | 0.004092010 |
| 14 | 0.001546100 |
| 15 | 0.000584169 |
Appendix: Methodology
Hexagons have 7 hexagon children. Pentagons have 6 children: 5 hexagons and 1 pentagon.Cell counts
By definition, resolution 0 has 110110 hexagons and 1212 pentagons, for a total of 122122 cells.
In fact, every H3 resolution has exactly 1212 pentagons, which are always centered at the icosahedron vertices; the number of hexagons increases with each resolution.
FormulaAccounting for both hexagons and pentagons, the total number of cells at resolution rr is
c(r)=2+120⋅7r.c(r) = 2 + 120 \cdot 7^r.Derivation of the cell count formula
We can derive the formula above with the following steps.
First, let h(n)h(n) be the number of children n≥0n \geq 0 resolution levels below any single hexagaon. Any hexagon has 77 immediate children, so recursion gives us that
h(n)=7n.h(n) = 7^n.Next, let p(n)p(n) be the number of children n≥0n \geq 0 resolution levels below any single pentagon. Any pentagon has 55 hexagonal immediate children and 11 pentagonal immediate child. Thus, p(0)=1p(0) = 1 and p(1)=6p(1) = 6.
For n≥1n \geq 1, we get the general recurrence relation
p(n)=5⋅h(n−1)+p(n−1)=5⋅7n−1+p(n−1).\begin{aligned} p(n) &= 5 \cdot h(n-1) + p(n-1) \\ &= 5 \cdot 7^{n-1} + p(n-1). \end{aligned}For n≥0n \geq 0, after working through the recurrence, we get that
p(n)=1+5⋅∑k=1n 7k−1=1+5⋅7n−16,\begin{aligned} p(n) &= 1 + 5 \cdot \sum_{k=1}^n\ 7^{k-1} \\ &= 1 + 5 \cdot \frac{7^n - 1}{6}, \end{aligned}using the closed form for a geometric series.
Finally, using the closed forms for h(n)h(n) and p(n)p(n), and the fact that (by definition) resolution 0 has 1212 pentagons and 110110 hexagons, we get the closed form for the total number of cells at resolution rr as
c(r)=12⋅p(r)+110⋅h(r)=2+120⋅7r.\begin{aligned} c(r) &= 12 \cdot p(r) + 110 \cdot h(r) \\ &= 2 + 120 \cdot 7^r. \end{aligned}Jupyter notebook
A notebook to produce the cell count table above can be found here.
Cell areas
Cell areas are computed with a spherical model of the earth using the authalic radius given by WGS84/EPSG:4326.
The h3-py-notebooks repo has notebooks for producing the average cell area table and the min/max area table.
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