The PH Of A 0.02 M NH4Cl Solution Will Be - Vedantu

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• The pH of a 002 M NH4Cl soluti...

AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsThe pH of a 0.02 M \[N{{H}_{4}}Cl\] solution will be: [given \[{{K}_{b}}(N{{H}_{4}}OH)={{10}^{-5}}\]and log 2 = 0.301].A. 4.65B. 5.35C. 4.35D. 2.65AnswerVerified595.5k+ viewsHint: Ammonium chloride (\[N{{H}_{4}}Cl\]) is a salt formed by the reaction of a strong acid (HCl) and a weak base (\[N{{H}_{4}}OH\]).The chemical reaction between HCl and \[N{{H}_{4}}OH\]is as follows.\[HCl+N{{H}_{4}}OH\to N{{H}_{4}}Cl+{{H}_{2}}O\]Complete step by step answer:-In the question it is given that the concentration of \[N{{H}_{4}}Cl\]is 0.02 M and base dissociation constant of \[N{{H}_{4}}OH\]is\[{{10}^{-5}}\]. - We have to find the pH of the 0.02 M \[N{{H}_{4}}Cl\] solution from the given data.-To calculate the pH of the \[N{{H}_{4}}Cl\]solution (formed by strong acid and weak base) there is a formula. The formula is as follows.\[pH=7-\dfrac{1}{2}[{{p}{{{K}_{b}}}}+\log C]\]Here pH = pH of the salt solution\[{{K}_{b}}\] = base dissociation constant (\[{{p}{{{K}_{b}}}}=-\log {{k}_{b}}\]) C = concentration of the salt - Now we have to substitute all the known values in the above formula to get the pH of the solution. \[\begin{align} & pH=7-\dfrac{1}{2}[{{p}{{{K}_{b}}}}+\log C] \\ & \text{ = 7}-\dfrac{1}{2}[\log {{10}^{-5}}+\log 0.02] \\ & \text{ = 7}-\dfrac{5}{2}-\dfrac{1}{2}(\log 2\times {{10}^{-2}}) \\ & \text{ = 5}\text{.35} \\ \end{align}\]-Therefore the pH of the ammonium chloride solution is 5.35.-So, the correct option is B. Note: Strong acid is an acid which dissolves in an aqueous solution and dissociates completely in less time. Example for a strong acid is Hydrochloric acid (HCl). Weak acid is an acid which does not dissociate completely in an aqueous solution. Example for weak acid is acetic acid (\[C{{H}_{3}}COOH\]). Strong base is a base which dissolves in an aqueous solution and dissociates completely in less time. Example for a strong base is sodium hydroxide (NaOH).Weak base is a base which does not dissociate completely in an aqueous solution. Example for a weak base is ammonium hydroxide (\[N{{H}_{4}}OH\]). Recently Updated PagesMaster Class 11 Business Studies: Engaging Questions & Answers for SuccessMaster Class 11 Computer Science: Engaging Questions & Answers for SuccessMaster Class 11 Economics: Engaging Questions & Answers for SuccessMaster Class 11 Social Science: Engaging Questions & Answers for SuccessMaster Class 11 English: Engaging Questions & Answers for SuccessMaster Class 11 Chemistry: Engaging Questions & Answers for SuccessMaster Class 11 Business Studies: Engaging Questions & Answers for SuccessMaster Class 11 Computer Science: Engaging Questions & Answers for SuccessMaster Class 11 Economics: Engaging Questions & Answers for SuccessMaster Class 11 Social Science: Engaging Questions & Answers for SuccessMaster Class 11 English: Engaging Questions & Answers for SuccessMaster Class 11 Chemistry: Engaging Questions & Answers for Success

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