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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIChemistryNCERTQuestionThe reaction of cyanamide NH2CN(s) with dioxygen was carried out in a bomb calorimeter and △U was found to be −742.7kJmol−1 at 298 K. NH2CN(g)+32O2(g)→N2(g)+CO2(g)+H2O(l)Calculate enthalpy change for the reaction at 298 K?Open in AppSolutionVerified by Toppr
For given reaction, Δn=1+1−1.5=0.5.ΔH=ΔU+ΔngRT=−742.7+0.5×8.314×10−3×298=−742.7+1.2=−741.5kJmole−1
Was this answer helpful?235Similar QuestionsQ1The reaction of cyanamide NH2CN(s) with dioxygen was carried out in a bomb calorimeter and △U was found to be −742.7kJmol−1 at 298 K. NH2CN(g)+32O2(g)→N2(g)+CO2(g)+H2O(l)Calculate enthalpy change for the reaction at 298 K?View SolutionQ2The reaction of cyan-amide, NH2CN(s), with dioxygen was carried out in a bomb calorimeter, and ΔU was found to be −742.7kJmol−1 at 298 K. Calculate enthalpy change for the reaction at 298 K.NH2CN(g)+32O2(g)→N2(g)+CO2(g)+H2O(l)View SolutionQ3The reaction of cyanamide, NH2CN(s), with dioxygen was carried out in a bomb calorimeter, and ΔU was found to be −742.7kJmol−1 at 298 K. calculate enthalpy change for the reaction at 298 K. NH2CN(g)+32O2(g)→N2(g)+CO2(g)+H2O(l)
View SolutionQ4The reaction of cyanamide NH2CN(s) with dioxygen was carried out in a bomb calorimeter and ΔU was found to be −742.7 kJmol−1 at 298K. Calculate enthalpy change for the following reaction at 298K. NH2CN(s)+32O2(g)→N2(g)+CO2(g)+H2O(l)View SolutionQ5The reaction of cyanamide (NH2CN) with dioxygen was carried out in a bomb calorimeter and ΔU was found to be −742.7kJmol−1 at 298K. Calculate the enthalpy change for the reaction at 298K NH2CN(s)+32O2(g)→N2(g)+CO2(g)+H2O(l)View SolutionTừ khóa » Nh2cn
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