The Sequence Xn Is Defined As Follows: Xn = 2X(n-1) - 1 - GMAT Club

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Back to Forum Create Topic Reply The sequence Xn is defined as follows: Xn = 2X(n-1) - 1 User avatar Bunuel User avatar Bunuel Math Expert Joined: 02 Sep 2009 Last visit: 22 Dec 2025 Posts: 106,363 Products: GMAT Club Tests Forum Quiz Expert Expert reply Active GMAT Club Expert! Tag them with @ followed by their username for a faster response. Posts: 106,363 The sequence Xn is defined as follows: Xn = 2X(n-1) - 1 Post URL 27 Oct 2021, 04:45 Show timer 00:00 Start Timer Pause Timer Resume Timer Show Answer a2% b5% c18% d70% e5% A B C D E Hide Show History My Mistake Official Answer and Stats are available only to registered users. Register/Login. Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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Date Time Result Not Attempted Yet The sequence \(X_{n}\) is defined as follows: \(X_{n} = 2X_{(n-1)}-1\) whenever n is an integer greater than 1. If \(X_1=3\), what is the value of \(X_{20} - X_{19}\)?(A) \(2^{16}\)(B) \(2^{17}\)(C) \(2^{18}\)(D) \(2^{19}\)(E) \(2^{20}\) ShowHide Answer Official Answer Official Answer and Stats are available only to registered users. Register/Login. _________________ - Win $39K in Prizes: Admissions Consulting Packages, Courses, Tests, and more in 12 Days of Christmas CompetitionNew to the GMAT Club?
    • Questions: Question Bank | Bunuel's Signature Collection• Tests: GMAT Club Tests | Forum Quiz• Guides: Quantitative | Verbal | Ultimate Quantitative Collection | All You Need for Quant• Rules: Quantitative | Verbal
Signature Read More Kudos Add Kudos 18 Bookmarks Bookmark this Post User avatar sanjitscorps18 User avatar sanjitscorps18 Joined: 26 Jan 2019 Last visit: 22 Dec 2025 Posts: 683 Location: India Schools: IMD'26 Products: My Reviews GMAT Club Tests Schools: IMD'26 Posts: 683 The sequence Xn is defined as follows: Xn = 2X(n-1) - 1 Post URL 27 Oct 2021, 05:03 Xn=2X(n−1)−1 whenever n is an integer greater than 1. X1=3, Value of X20−X19 = 2X19 - 1 -X19 = X19 - 1If we build the series (X1, X2, X3, X4 .....) we get 3, 5, 9, 17 ......This is essentially 2^1 + 1 , 2^2 + 1 , 2^3 + 1 , 2^4 + 1 ......Hence X19 = 2^19 + 1=> X20−X19 = X19 - 1 = 2^19 + 1 - 1 = 2^19IMO Option D 1 Kudos Add Kudos Bookmarks Bookmark this Post User avatar rayjaycleoful User avatar rayjaycleoful Joined: 15 May 2021 Last visit: 22 Dec 2025 Posts: 33 Posts: 33 The sequence Xn is defined as follows: Xn = 2X(n-1) - 1 Post URL 16 Nov 2023, 21:07 BunuelThe sequence \(X_{n}\) is defined as follows: \(X_{n} = 2X_{(n-1)}-1\) whenever n is an integer greater than 1. If \(X_1=3\), what is the value of \(X_{20} - X_{19}\)?(A) \(2^{16}\)(B) \(2^{17}\)(C) \(2^{18}\)(D) \(2^{19}\)(E) \(2^{20}\)Show more Could someone explain how we get 5,9, 17... when we expand X2,X3,X4....? Kudos Add Kudos Bookmarks Bookmark this Post User avatar Bunuel User avatar Bunuel Math Expert Joined: 02 Sep 2009 Last visit: 22 Dec 2025 Posts: 106,363 Products: GMAT Club Tests Forum Quiz Expert Expert reply Active GMAT Club Expert! Tag them with @ followed by their username for a faster response. Posts: 106,363 The sequence Xn is defined as follows: Xn = 2X(n-1) - 1 Post URL 16 Nov 2023, 23:02 rayjaycleofulBunuelThe sequence \(X_{n}\) is defined as follows: \(X_{n} = 2X_{(n-1)}-1\) whenever n is an integer greater than 1. If \(X_1=3\), what is the value of \(X_{20} - X_{19}\)?(A) \(2^{16}\)(B) \(2^{17}\)(C) \(2^{18}\)(D) \(2^{19}\)(E) \(2^{20}\)Could someone explain how we get 5,9, 17... when we expand X2,X3,X4....?Show more The formula \(X_{n} = 2X_{(n-1)} - 1\) is used to determine the \(n^{th}\) term of the sequence \(X_n\), given the preceding \(n-1^{th}\) term, \(X_{n-1}\).Starting with \(X_1 = 3\), the subsequent term, \(X_2\), is calculated as follows:\(X_{2} = 2X_{1} - 1 = 2 * 3 - 1 = 5\).Similarly:\(X_{3} = 2X_{2} - 1 = 2 *5 - 1 = 9\).And so on.Check the links below for more:

12. Sequences

  • TheorySequences Made Easy - All in One Topic!Math : Sequences & ProgressionsTime to Tackle Geometric Progressions!
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Signature Read More 1 Kudos Add Kudos Bookmarks Bookmark this Post User avatar shuvamp User avatar shuvamp Joined: 28 Nov 2016 Last visit: 06 Jan 2025 Posts: 8 Location: India Concentration: Operations, Marketing Schools: S.P.Jain Institute GMAT 1: 700 Q50 V37 GPA: 3.14 WE:Engineering (Energy) Schools: S.P.Jain Institute GMAT 1: 700 Q50 V37 Posts: 8 The sequence Xn is defined as follows: Xn = 2X(n-1) - 1 Post URL 05 Jan 2024, 23:33 Xn=2X(n−1)−1...... equation 1X1=3Solving equation 1 for n=2,3,4,5..... we get, X2=2X1-1=2x3-1=5X3=9X4=17X5=33we observe that, difference between consecutive numbers in the sequence is in 2^nX2-X1=5-3=2X3-X2=9-5=4=2^2X4-X3=17-9=8=2^3X5-X4=33-17=16=2^4HENCE, X20-X19=2^19, OPTION D Kudos Add Kudos Bookmarks Bookmark this Post NEW TOPIC POST REPLY Question banks Downloads My Bookmarks Important topics Reviews Moderators: Bunuel Math Expert 106363 posts Krunaal Tuck School Moderator 810 posts Competiton Image Join the GMAT Competition with $30K Prize Fund Join Learn more

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