The Value Of Acceleration Due To Gravity Is 980cms Class 12 Physics ...

CoursesCourses for KidsFree study materialOffline CentresMoreStore

Talk to our experts

1800-120-456-456

Sign In

• Question Answer

• Class 12

• Physics

• The value of acceleration due ...

AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsThe value of acceleration due to gravity is $980\,cm{s^{ - 2}}$. What will be its value if the unit of length is kilometre and that time is minute?AnswerVerified498.6k+ viewsHint: Let us first get some idea about the acceleration due to gravity. The acceleration gained by an object due to gravitational force is known as acceleration owing to gravity. The SI unit for it is \[m \times {s^{ - 2}}\].It is a vector quantity since it has both magnitude and direction. The acceleration owing to gravity is denoted by the letter$g$. $g$ has a standard value of \[9.8{\text{ }}m{s^{ - 2}}\] on the earth's surface at sea level. Complete step-by-step solution:As given in the problem:$g = 980\,cm{s^{ - 2}}$As we know that:$1\,cm = \dfrac{1}{{{{10}^5}}}km$ and $1s = \dfrac{1}{{60}}\min $Now, if we substitute the above value in the g then we will get:$g = 980 \times {10^{ - 5}} \times 60 \times 60\,km/{\min ^2}$$g = 35.28\,km/{\min ^2}$Additional Information:Variation of $g$ due to shape of Earth:The earth's radius at the equator is greater than its radius at the poles because it is an oblate spheroid. Because the acceleration due to gravity for a source mass is inversely proportional to the square of the earth's radius, it varies with latitude due to the earth's shape.$\dfrac{{{g_p}}}{{{g_e}}} = \dfrac{{R_e^2}}{{R_p^2}}$Where ${g_e}$ and${g_p}$ are the gravitational accelerations at the equator and poles, respectively, and \[{R_e}\]and \[{R_p}\]are the earth's radii near the equator and poles. It is obvious from the preceding equation that gravity accelerates more near the poles and less in the equator. As the value of g drops, a person's weight falls as he moves from the equator to the poles.Note: In order to solve this problem there are some important points which we should keep in our fingertips. Unit conversion is the most important point to solve this problem. These are the some conversion we should keep in our mind: $10\,mil\lim eters\,(mm) = 1\,centimeter\,(cm)$ $10\,centimeters = 1\,decimeter\,(dm) = 100\,mil\lim eters$$100\,centimeter = 1\,meter(m) = 1000\,mil\lim eters$$1000\,meters = 1\,kilometer\,(km)$.Recently Updated PagesMaster Class 12 Business Studies: Engaging Questions & Answers for SuccessMaster Class 12 Economics: Engaging Questions & Answers for SuccessMaster Class 12 English: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Social Science: Engaging Questions & Answers for SuccessMaster Class 12 Chemistry: Engaging Questions & Answers for SuccessMaster Class 12 Business Studies: Engaging Questions & Answers for SuccessMaster Class 12 Economics: Engaging Questions & Answers for SuccessMaster Class 12 English: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Social Science: Engaging Questions & Answers for SuccessMaster Class 12 Chemistry: Engaging Questions & Answers for Success

• 1
• 2

Trending doubtsWhat are the major means of transport Explain each class 12 social science CBSEWhich are the Top 10 Largest Countries of the World?Draw a labelled sketch of the human eye class 12 physics CBSEExplain sex determination in humans with line diag class 12 biology CBSEThe pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSEExplain sex determination in humans with the help of class 12 biology CBSEWhat are the major means of transport Explain each class 12 social science CBSEWhich are the Top 10 Largest Countries of the World?Draw a labelled sketch of the human eye class 12 physics CBSEExplain sex determination in humans with line diag class 12 biology CBSEThe pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSEExplain sex determination in humans with the help of class 12 biology CBSE

• 1
• 2

Repeaters Course for NEET 2022 - 23

NEET Repeater 2023 - Aakrosh 1 Year Course