The Value Of C0+3C1+5C2+7C3++2n+1Cn Is Equal To 2n 2n
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The value of C0+3C1+5C2+7C3++2n+1Cn is equal to 2n 2n
| Related Questions
| The value of C0+3C1+5C2+7C3+....+(2n+1)Cn is equal to :
A.
2n
B.
2n+n.2n−1
C.
2n(n+1)
D.
None of these
Please scroll down to see the correct answer and solution guide.
Right Answer is: C
SOLUTION
C0+3C1+5C2+7C3+.....
=(C0+C1+C2+⋯)+2(C1+2C2+3C3+⋯)
=2n+2.n.2n−1=(n+1)2n
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The Sum of the coefficients in x+2y+z10 is 210 310 1 41If every pair among the equations x2+px+qr=0 x2+qx+rp=0The Value of 14C2+14C3+14C4++14C14 is 214−14 214−15The length of the sides of a triangle are xy and √x2+y2Từ khóa » C0+3c1+5c2
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