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Go back to my question iPhone User profile for user: Schwaben10 Schwaben10 Author User level: Level 1 54 points Trig functions on iPhone calculator?

On the scientific calculator on my iPhone 4, I see the buttons for sine, cosine, and tangent, but how do I get secant, cosecant, and cotangent? And what are sinh, cosh, and tanh?

Thanks.

Posted on May 21, 2013 6:30 PM

Me too (247) Me too Me too (247) Me too Reply 6 replies

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User profile for user: randers4 randers4 User level: Level 9 63,567 points

May 21, 2013 7:01 PM in response to Schwaben10

The "h" functions are hyperbolic functions (hyperbolic sine, consine and tangent); see http://en.wikipedia.org/wiki/Hyperbolic_function.

Secant, cosecant and cotangent can be calculated as the reciprocal of cosine, sine and tangent using teh 1/x function (see http://en.wikipedia.org/wiki/Trigonometric_functions#Reciprocal_functions).

The app store is full of alternative calulators as well, including reproductions of some of the Hewlett Packard ones such as the 15C.

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User profile for user: randers4 randers4 User level: Level 9 63,567 points

May 21, 2013 7:19 PM in response to Schwaben10

You're welcome. I'm sure there are plenty of practice problems available on the internet. Try googling something like "trig function practice problems". Here's one at random: http://serc.carleton.edu/mathyouneed/trigonometry/BasicTrigSP.html.

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User profile for user: Ocean20 Ocean20 User level: Level 6 13,733 points

May 21, 2013 7:02 PM in response to Schwaben10

Read http://en.wikipedia.org/wiki/Hyperbolic_function

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User profile for user: Schwaben10 Schwaben10 Author User level: Level 1 54 points

May 21, 2013 7:12 PM in response to randers4

Thanks. I need to learn the right-angle functions for machining. Do you know where I can find practice exercises?

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User profile for user: Schwaben10 Schwaben10 Author User level: Level 1 54 points

May 21, 2013 7:38 PM in response to randers4

Good idea. Thanks again!

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User profile for user: randers4 randers4 User level: Level 9 63,567 points

May 21, 2013 7:39 PM in response to Schwaben10

You're welcome. Good luck!

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