Unit 17 Section 3 : Quadratic Equations: Completing The Square
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Completing the square is a useful technique for solving quadratic equations. It is a more powerful technique than factorisation because it can be applied to equations that do not factorise.
When completing the square, an expression like,
ax^2 + bx + c is written in the form (Ax + B)^2 + C.
We will begin with the simple example where a = 1. In this case we will write expressions in the form
x^2 + bx + c as (x + B)^2 + C
If we expand (x + B)^2 + C we get x^2 + 2Bx + B^2 + C.
Comparing this with x^2 + bx + c shows that
b = 2B and c = B^2 + C
which gives B = and C = c - B^2
Using these two results we can now set about completing the square in some simple cases.
Example 1
Write each of the following expressions in the form (x + B)^2 + C.
(a)x^2 + 6x + 1
Comparing x^2 + 6x + 1 with x^2 + bx + c we see that b = 6 and c = 1 in this case, so
B = = = 3 and C = c - B^2 = 1 - 3^2 = -8.
Therefore x^2 + 6x + 1 = (x + 3)^2 - 8.
(b)x^2 + 4x - 2
Here b = 4 and c = –2, so
B = = = 2 and C = c - B^2 = (-2) - 2^2 = -6.
Therefore x^2 + 4x - 2 = (x + 2)^2 - 6.
(c)x^2 + 2x
Here B = = 1 and C = 0 - 1^2 = -1, so x^2 + 2x = (x + 1)^2 - 1.
Example 2
Solve the following equations by completing the square.
(a)x^2 - 4x - 5 = 0
Completing the square gives,
x^2 - 4x - 5 = (x - 2)^2 - 9
Now we can solve the equation
(x – 2)2 | = 9 |
x – 2 | = ± |
x – 2 | = ± 3 |
x | = 2 ± 3 |
sox | = 5 or –1 |
x^2 + 6x - 1 = 0
Completing the square gives,
x^2 + 6x - 1 = (x + 3)^2 - 10
Now we can solve the equation
(x + 3)2 | = 10 |
x + 3 | = ± |
x | = –3 ± |
sox | = 0.162 or –6.162 to 3 decimal places |
Exercises
Note: To type indeces on this page use ^ sign. e.g. n2: Question 1Write each of the following expressions in the form (x + B)2 + C.
(a) | x^2 + 6x | ( )2 |
---|---|---|
(b) | x^2 + 4x | ( )2 |
(c) | x^2 + 8x | ( )2 |
(d) | x^2 - 10x | ( )2 |
(e) | x^2 + 7x | ( )2 |
(f) | x^2 - 5x | ( )2 |
Write each of the following expressions in the form (x + B)2 + C:
(a) | x^2 + 6x + 1 | ( )2 |
---|---|---|
(b) | x^2 - 8x + 3 | ( )2 |
(c) | x^2 + 10x - 12 | ( )2 |
(d) | x^2 + 12x + 8 | ( )2 |
(e) | x^2 - 4x + 1 | ( )2 |
(f) | x^2 - 6x - 3 | ( )2 |
(g) | x^2 + 5x + 3 | ( )2 |
(h) | x^2 + 3x - 4 | ( )2 |
(i) | x^2 + x - 2 | ( )2 |
(j) | x^2 - x + 3 | ( )2 |
Solve each of the following quadratic equation by completing the square:
(a) | x^2 - 2x - 8 = 0 | x = or x = |
---|---|---|
(b) | x^2 + 4x + 3 = 0 | x = or x = |
(c) | x^2 + 8x + 12 = 0 | x = or x = |
(d) | x^2 - 5x + 4 = 0 | x = or x = |
(e) | x^2 - 2x - 15 = 0 | x = or x = |
(f) | x^2 + 3x - 28 = 0 | x = or x = |
Solve each of the following quadratic equations by completing the square. Give your answers to 2 decimal places.
(a) | x^2 + 2x - 5 = 0 | x = or x = |
---|---|---|
(b) | x^2 + 4x - 1 = 0 | x = or x = |
(c) | x^2 + 6x - 5 = 0 | x = or x = |
(d) | x^2 - 10x - 1 = 0 | x = or x = |
(e) | x^2 + x - 3 = 0 | x = or x = |
(f) | x^2 - 3x + 1 = 0 | x = or x = |
(g) | x^2 + 5x - 4 = 0 | x = or x = |
(h) | x^2 + 3x - 5 = 0 | x = or x = |
The rectangle shown has an area of 20 cm² .
(a)Write down an equation for the width x of the rectangle.
This equation can be simplified to x^2 + 4x - 20 = 0. (b)Use completing the square to determine the width of the rectangle to 2 decimal places.
Width = cm Question 6 (a)Write the equation x^2 - 8x + 18 in the form (x + B)2 + C = 0.
( )2 (b)How many solutions has this equation?
- 0 1 2 The equation has no solution, because (x - 4)^2 cannot be negative. Question 7Simplify each of the following equations and obtain their solutions by completing the square.
(a) | 4x^2 + 20x - 8 = 0 | x = or x = |
---|---|---|
(b) | 20x^2 - 40x + 60 = 0 | x = or x = |
(c) | 3x^2 + 6x - 9 = 0 | x = or x = |
(d) | 5x^2 - 30x - 15 = 0 | x = or x = |
The height of a ball at time t seconds can be calculated by using the formula
h = 20t - 5t^2
(a)Calculate the value of h when t = 2.
h = (b)Determine the values of t for which h = 15.
t = or t = Question 9The area of the rectangle shown is 30 cm². Determine the value of x.
x = Question 10The area of the triangle shown is 120 cm². Determine the perimeter of the triangle correct to the nearest millimetre.
Perimeter = cm Question 11Use the method of completing the square or the appropriate formula to solve x^2 + 4x - 2 = 0. Write your answers to 2 decimal places.
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