Using The Remainder Theorem, Find The Remainder, When P(x) Is ...

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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard IXMathsRemainder TheoremQuestionUsing the remainder theorem, find the remainder, when $$p(x)$$ is divided by $$g(x)$$, where $$p(x)=x^3-6x^2+9x+3$$, $$g(x)=x-1$$.Open in AppSolutionVerified by Toppr

$$p(x)=x^3-6x^2+9x+3$$$$g(x)=x-1$$$$x-1=0$$$$x=1$$$$p(1)=(1)^3-6(1)^2+9×1+3$$$$=1-6+9+3$$$$=-5+9+3$$$$=4+3$$$$=7$$

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Using the remainder theorem, find the remainder, when p(x) is divided by g(x), where (px)=x3−6x2+9x+3,g(x)=x−1

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