The volume occupied by 8 gm of oxygen at S.T.P. is - Toppr www.toppr.com › ... › Ideal Gas Equation and Absolute Temperature
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The volume of 8 g of O2 at STP is: · 22.4 L · 11.2 L · 5.6 L · 2.24 L.
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Q. The volume occupied by 8 gm of oxygen at S.T.P. is · 11.2 lit · 22.4 lit · 2.8 lit · 5.6 lit · 32 gm of oxygen =1 mole =22.4 lit (standard result according to gas ...
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AMU 2013: The volume occupied by 16 g of oxygen gas at STP is (A) 22.4 L (B) 44.8 L (C) 11.2 L (D) 5.6 L. Check Answer and Solution for above question.
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Answer:11.2 Explanation:1 mole of O2 = 16 g0.5 moles of O2 = 8g { since n = m/M where n is the no. of moles m is the given mass …
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Molecular weight of oxygen = 32 g 32 g of oxygen occupies 22.4 L volume at STP 8 g of oxygen will occupy volume .
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Thời lượng: 3:32 Đã đăng: 27 thg 6, 2022 VIDEO
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Đã đăng: 10 thg 5, 2021 VIDEO
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Aug 05,2022 - 8 g of O2 gas at STP is expanded so that volume is doubled. Thus, work done isa)22.4 L atmb)11.2L atmc)5.6L atmd)- 5.6L atmCorrect answer is ...
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6 g of O 2 gas at STP is expanded against atmosphere so that the volume is doubled. Thus, the work done is:A. 22.4 L atmB. 4.2 L atmC. 5.6 L atmD.
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1.8 g oxygen occupies (22.4/32)×1.8 = 1.26 L. Hope, this helps.
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30cm3 of methane is completely burned in 100cm3 of oxygen. What is the volume and composition of the gas at the end of the experiment? (All volumes are. Bị thiếu: stp | Phải bao gồm: stp
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For finding the gram equivalent volume of oxygen( O2), we equate the following: $ 32g $ of $ {{O}_{2}}\to 22.4L $ of $ {{O}_{2}} $ . So, $ 8g $ is ...
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8 gram of oxygen gas at S.T.P. is expanded so that the volume is doubled. the work done during this process is. number of moles of 8g oxygen = 0.25 moles ...
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Download Free solutions of NCERT chemistry Class 11th from SaralStudy. SaralStudy helps in prepare for NCERT CBSE solutions for Class 11th chemistry. was ...
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