What Is The Range Of The Function F(x)=(5x-3)/(2x+1)? | Socratic
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2 Answers
Narad T. Jul 26, 2017The range is #y in RR-{5/2}#
Explanation:
#f(x)=(5x-3)/(2x+1)# Let
#y=(5x-3)/(2x+1)#
#y(2x+1)=5x-3#
#2yx+y=5x-3#
#5x-2yx=y+3#
#x(5-2y)=(y+3)#
#x=(y+3)/(5-2y)#
The domain of #x=f(y)# is #y in RR-{5/2}#
This is also #f^-1(x)=(x+3)/(5-2x)#
graph{(5x-3)/(2x+1) [-22.8, 22.83, -11.4, 11.4]}
Answer link Jim G. Jul 26, 2017#y inRR,y!=5/2#
Explanation:
Answer link#"given "y=(5x-3)/(2x+1)#
#"rearrange making x the subject"#
#rArry(2x+1)=5x-3larrcolor(blue)"cross-multiplying"#
#rArr2xy+y=5x-3larrcolor(blue)" distributing"#
#rArr2xy-5x=-3-ylarrcolor(blue)" collect terms in x"#
#rArrx(2y-5)=-(3+y)larrcolor(blue)" factor out x"#
#rArrx=-(3+y)/(2y-5)#
#"the denominator cannot equal zero as this would"# #"be undefined"#
#2y-5=0rArry=5/2larrcolor(red)" excluded value"#
#"range is "y inRR,y!=5/2#
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