What Should Be The IUPAC Name Of (NH3)5Co-NH2-Co(NH3)4(H2O)]?

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Learn more about Teams What should be the IUPAC name of [(NH3)5Co-NH2-Co(NH3)4(H2O)]? Ask Question Asked 3 years, 4 months ago Modified 7 months ago Viewed 2k times 6 $\begingroup$

What should be the IUPAC name of $\ce{(NH3)5Co-NH2-Co(NH3)4(H2O)]}$?

This is similar to $\ce{[(NH3)5Co-NH2-Co(NH3)5](NO3)5}$, i.e. μ-amido-bis[pentaamminecobalt(III)] nitrate. But the two parts are different.

• inorganic-chemistry
• nomenclature
• coordination-compounds

Share Cite Improve this question Follow edited Mar 16 at 2:03 Mithoron 4,6271414 gold badges4141 silver badges6262 bronze badges asked Jul 17, 2021 at 13:25 Hank WHank W 7966 bronze badges $\endgroup$ 4

• 1 $\begingroup$ Related : Inorganic IUPAC for Compounds with bridged ligands? $\endgroup$ – Harikrishnan M Commented Mar 11 at 16:22
• 1 $\begingroup$ The name of the listed product is said as $\ce{Co_2(NH_3)_9(NH_4)(H_2O)}$ $\endgroup$ – user144448 Commented Mar 15 at 16:59
• $\begingroup$ @HarikrishnanM-you might delete this comment of mine after you replace the $\ce{(NH_4)}$ with $\ce{(NH_2)}$ in the comment which I posted here on March 15 at 16:59 hours $\endgroup$ – user158257 Commented Sep 22 at 6:30
• $\begingroup$ @HarikrishnanM-you might delete this comment of mine after you replace the $\ce{(NH_4)}$ with $\ce{(NH_2)}$ in the comment which I posted here on March 15 at 16:59 hours $\endgroup$ – user158257 Commented Sep 22 at 6:35

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Nomenclature for Bridged Coordination Compounds

I shall respond to this question with all the rules to be followed when there is a compound in the given formats:

1. $\ce{[L_1M_1 < (1-2 ligands) > M_2L_2]^n+}$
2. $\ce{[L_1M_1 < (1-2 ligands) > M_1L_1]^n+}$

I hope you are familiar with the basic rules to be followed (ligands in alphabetical order, oxidation number written at the end in Roman numerals, atom of the ligand bonding with metal to be written in the case of ambidentate ligands, etc...). You can look up here - I have linked a Chemistry LibreTexts document.

Rule 1: The ligands in the middle should be written with the Greek letter $\mu_n$ prefixed to it - where $n$ indicates the number of atoms to which the ligand is bonded. In practice, the subscript $n$ is omitted when $n=2$. For ease of reference, we'll call this part of the name Part 1.

Rule 2: The metal atoms must be named separately - $\ce{L_1M_1}$ and $\ce{M_2L_2}$. Call this part of the name as Part 2 and Part 3 respectively. The OP has named an example - $\ce{[(NH3)5Co−NH2−Co(NH3)5](NO3)5}$ is called μ-amido-bis[pentaamminecobalt(III)] nitrate.

Rule 3: If metal + ligand part is repetitive, use prefix bis-, tris-, tetrakis- etc.

Oxidation numbers should be included separately, and for an individual metal, it is calculated by taking net negative charged ligands around it.

The final name would be in the format $\mathbf{\text{Part 2 Part 1 Part 3}}$.

The compound in your contention, $\ce{[\color{red}{(NH3)5Co}-\color{blue}{NH2}-\color{magenta}{Co(NH3)4(H2O)}]}$ : I have divided it into 3 parts (refer to the colour scheme).

The $\ce{\color{red}{red part}}$ is named pentaamminecobalt(III).

The $\ce{\color{blue}{blue part}}$ is named μ-amido.

The $\ce{\color{magenta}{pink part}}$ is named tetraammineaquacobalt(III).

Merging all the parts together:

pentaamminecobalt(III)-μ-amido-tetraammineaquacobalt(III).

Another example for your understanding:

is named as

Tetraamminechromium(III)-μ-amido-μ-hydroxidobis(ethylenediamine)cobalt(III) ion.

Sources:

1. LibreTexts - Inorganic Chemistry - Coordination Chemistry - Nomenclature

Share Cite Improve this answer Follow edited Apr 19 at 23:14 Melanie Shebel 6,8021010 gold badges4848 silver badges8888 bronze badges answered Mar 15 at 1:38 Harikrishnan MHarikrishnan M 83855 silver badges3232 bronze badges $\endgroup$ 0 Add a comment |

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