When Stearic Acid Left C18H36O2 Right Is Added To Water Class 11 ...

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AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsWhen stearic acid \[\left( {{C_{18}}{H_{36}}{O_2}} \right)\] is added to water, its molecules collect at the surface and form a monolayer. The cross-sectional area of each stearic acid molecule is \[0.21n{m^2}\]. If \[1.4 \times {10^{ - 4}}g\] of stearic acid is needed to form a monolayer over water in a dish of diameter\[20cm\]. (The area of the circle of the radius \[r\] is \[\left( {\pi {r^2}} \right)\], then the value of Avogadro’s number is:A. \[3 \times {10^{23}}\]B. \[6 \times {10^{23}}\]C. \[4 \times {10^{23}}\]D. \[1 \times {10^{23}}\]AnswerVerified529.8k+ viewsHint: To answer this problem first we need to be clear about the basic concepts first, one mole of a substance is equivalent to \[6.022 \times {10^{23}}\] units of that substance, particles or atoms. The number \[6.022 \times {10^{23}}\] is known as Avogadro's number or Avogadro's constant. The Avogadro number is the proportionality factor that relates the number of constituent particles in a sample with the amount of substance in that sample.Complete step-by-step answer:The area of the dish of \[20cm\] in diameter which is given in the question is given by the formula \[\pi {r^2}\] Hence the radius is given by $r = \dfrac{{20}}{2} = 10cm = 0.01{m^2}$By substituting the values, the formula for area is given as,$\pi \times 0.01{m^2}$As given in the question \[0.21 \times {10^{ - 18}}{m^2}\]is the area of one moleculeHence, \[\pi \times 0.01{m^2}\]is the area of \[ = \dfrac{{\pi \times 0.01}}{{0.21 \times {{10}^{ - 18}}}}\]moleculesSince the molecular weight of stearic acid is $284g/mol$.The number of moles of stearic acid present in \[1.4 \times {10^{ - 4}}g\] of stearic acid is given as,\[1.4 \times {10^{ - 4}}g\]stearic acid \[ = \dfrac{{1.4 \times {{10}^{ - 4}}}}{{284}}mol\]\[ = \dfrac{{1.4 \times {{10}^{ - 4}}}}{{284}}{N_o}\]moleculesBy equating the number of molecules present in \[1.4 \times {10^{ - 4}}g\] of stearic acid and \[\dfrac{{\pi \times 0.01}}{{0.21 \times {{10}^{ - 18}}}}\] molecules we get,\[\ = \dfrac{{1.4 \times {{10}^{ - 4}}}}{{284}}{N_o} = \dfrac{{\pi \times 0.01}}{{0.21 \times {{10}^{ - 18}}}} \\ {N_o} = 3.30 \times {10^{23}} \\ 3.30 \times {10^{23}} \\ \ \]Therefore, Avogadro’s number is \[3.30 \times {10^{23}}\]Additional Information: Self-assembled monolayers (SAM) of natural molecules are molecular congregations shaped unexpectedly on surfaces by adsorption and are sorted out into pretty much enormous arranged domains. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction. So, the correct option is A. Note: Area is fairly that is occupied by an object when it is laying on a surface. That area is the space which is given by the object. Though cross-sectional area is an area which we acquire when a similar object is cut into two pieces. The area of that specific cross segment is known as cross sectional area. Recently Updated PagesMaster Class 12 Economics: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Biology: Engaging Questions & Answers for SuccessMaster Class 12 Physics: Engaging Questions & Answers for SuccessMaster Class 8 Maths: Engaging Questions & Answers for SuccessClass 8 Question and Answer - Your Ultimate Solutions GuideMaster Class 12 Economics: Engaging Questions & Answers for SuccessMaster Class 12 Maths: Engaging Questions & Answers for SuccessMaster Class 12 Biology: Engaging Questions & Answers for SuccessMaster Class 12 Physics: Engaging Questions & Answers for SuccessMaster Class 8 Maths: Engaging Questions & Answers for SuccessClass 8 Question and Answer - Your Ultimate Solutions Guide

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