X^2-6x+9=3x+1 - Solution

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x^2-6x+9=3x+1

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Solution for x^2-6x+9=3x+1 equation:

x^2-6x+9=3x+1 We move all terms to the left: x^2-6x+9-(3x+1)=0 We get rid of parentheses x^2-6x-3x-1+9=0 We add all the numbers together, and all the variables x^2-9x+8=0 a = 1; b = -9; c = +8;Δ = b2-4acΔ = -92-4·1·8Δ = 49The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$ $x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-7}{2*1}=\frac{2}{2} =1 $ $x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+7}{2*1}=\frac{16}{2} =8 $

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