Xn, Then The Value Of C0 - ​ - +2C1 - ​ - +3C2 - ​ - +....+(n+1)Cn

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  4. If (1 + x)n =C0 + C1x + C2x2 + ..... + Cn xn, then the value of C0 + 2C1 + 3C2 +....+ (n + 1) Cn will be
Q. If , then the value of will be 7137 240 COMEDKCOMEDK 2006Binomial Theorem Report Error A

38% B

0% C

62% D

0%

Solution:

Since, On differentiating w.r.t. x, we get Put x = 1, we get

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