Ch15: Reduction Of Aldehydes And Ketones - Chemistry
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| Chapter 15: Alcohols, Diols and Thiols |
Reductions of Aldehydes and Ketones
Reactions usually in Et2O or THF followed by H3O+ work-ups
Reaction type: Nucleophilic Addition
Summary
- Aldehydes and ketones are most readily reduced with hydride reagents
- The reducing agents LiAlH4 and NaBH4 act as a source of 4 x H- (hydride ion)
- Overall 2 H atoms are added across the C=O to give H-C-O-H
- Hydride reacts with the carbonyl group, C=O, in aldehydes or ketones to give alcohols.
- The substituents on the carbonyl dictate the nature of the product alcohol.
- Reduction of methanal (formaldehyde) gives methanol.
- Reduction of other aldehydes gives primary alcohols.
- Reduction of ketones gives secondary alcohols.
- The acidic work-up converts an intermediate metal alkoxide salt into the desired alcohol via a simple acid base reaction.
- Reduction of carboxylic acids and esters
- Reaction of RLi and RMgX with esters
- Reaction of RLi and RMgX with epoxides
- Reaction of RLi and RMgX with carbon dioxide
| NUCLEOPHILIC ADDITION OF LiAlH4 TO AN ALDEHYDE | |
| Step 1: The nucleophilic H in the hydride reagent adds to the electrophilic C in the polar carbonyl group in the aldehyde, electrons from the C=O move to the O creating an intermediate metal alkoxide complex. (note that all 4 of the H atoms can react) | |
| Step 2: This is the work-up step, a simple acid/base reaction. Protonation of the alkoxide oxygen creates the primary alcohol product from the intermediate complex. | |
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| © Dr. Ian Hunt, Department of Chemistry |
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