Tangent Line - Equation, Slope, Horizontal | Point Of Tangency

Tangent Line

The "tangent line" is one of the most important applications of differentiation. The word "tangent" comes from the Latin word "tangere" which means "to touch". The tangent line touches the curve at a point on the curve. So to find the tangent line equation, we need to know the equation of the curve (which is given by a function) and the point at which the tangent is drawn.

Let us see how to find the slope and equation of the tangent line along with a few solved examples. Also, let us see the steps to find the equation of the tangent line of a parametric curve and a polar curve.

1. What is Tangent Line?
2. Slope of Tangent Line
3. Tangent Line Equation
4. Tangent Line Approximation
5. Tangent Line Equation of Parametric Curve
6. Tangent Line of Polar Curve
7. FAQs on Tangent Line

What is Tangent Line?

The tangent line of a curve at a given point is a line that just touches the curve (function) at that point. The tangent line in calculus may touch the curve at any other point(s) and it also may cross the graph at some other point(s) as well. The point at which the tangent is drawn is known as the "point of tangency". We can see the tangent of a circle drawn here.

point of tangency

If a line passes through two points of the curve but it doesn't touch the curve at either of the points then it is NOT a tangent line of the curve at each of the two points. In that case, the line is called a secant line. Here, we can see some examples of tangent lines and secant lines. The following shows a secant line PQ but which is NOT a tangent either at P or at Q.

The secant line of a graph passing through two points P and Q is drawn on a curve.

Tangent Line Examples

Here is a typical example of a tangent line that touches the curve exactly at one point.

tanent line with one point of tangency

As we learned earlier, a tangent line can touch the curve at multiple points. Here is an example.

Tangent line examples

Again, the tangent line of a curve drawn at a point may cross the curve at some other point also. Here is the tangent line drawn at a point P but which crosses the curve at some other point Q.

The tangent line of a curve may cross the line at some other point also.

The above line PQ can also be called the secant line. A secant line may also pass through any two points of the curve without the need to touch the curve at each of the two points.

Slope of Tangent Line

Let us consider a curve that is represented by a function f(x). Also, let us consider a secant line passing through two points of the curve P (x0, f(x0)) and Q (x0 + h, f(x0 + h)). i.e., P and Q are at a distance of h units from each other.

The slope of tangent line proof is given.

Then the slope of the secant line using the slope formula is,

Slope of secant line = [f(x0 + h) - f(x0)] / (x0 + h - x0) = [f(x0 + h) - f(x0)] / h

From the above figure, we can see that if Q comes very close to P (by making h → 0) and merges with P, then the secant line becomes the tangent line at P. i.e., the slope of the tangent line at P can be obtained by applying h → 0 to the slope of the secant line. So

Slope of Tangent at P = limₕ → 0 [f(x0 + h) - f(x0)] / h

We know that this is nothing but the derivative of f(x) at x = x0 (by the limit definition of the derivative (or) first principles). i.e.,

  • Slope of Tangent at P = f '(x0)

Therefore, the slope of the tangent is nothing but the derivative of the function at the point where it is drawn.

Slope of Tangent Line Formula

The slope of the tangent line of y = f(x) at a point (x0, y0) is (dy/dx)(x0, y0) (or) (f '(x)) (x0, y0), where

  • f'(x) is the derivative of the function f(x).
  • (f '(x)) (x0, y0) is the value obtained by substituting (x, y) = (x0, y0) in the derivative f '(x).

Note that we may have to use implicit differentiation to find the derivative f '(x) if the function is implicitly defined.

Tangent Line Equation

We know that the equation of a line with slope 'm' that is passing through a point (x0, y0) is found by using the point-slope form: y - y0 = m (x - x0). Let us consider the tangent line drawn to a curve y = f(x) at a point (x0, y0). Then from the previous sections,

Slope of the tangent line, m = (f '(x)) (x0, y0)

By substituting m, x0, and y0 values in the point-slope form y - y0 = m (x - x0) we can get the tangent line equation.

Thus, the tangent line formula is,

  • y - y0 = (f '(x)) (x0, y0) (x - x0)

Steps to Find the Tangent Line Equation

To find the tangent line equation of a curve y = f(x) drawn at a point (x0, y0) (or at x = x0):

  • Step - 1: If the y-coordinate of the point is NOT given, i.e., if the question says the tangent is drawn at x = x0, then find the y-coordinate by substituting it in the function y = f(x). i.e., y-coordinate, y0 = f(x0).
  • Step - 2: Find the derivative of the function y = f(x) and represent it by f'(x).
  • Step - 3: Substitute the point (x0, y0) in the derivative f '(x) which gives the slope of the tangent (m).
  • Step - 4: Find the equation of the tangent using the point-slope form y - y0 = m (x - x0).

Tangent Line Approximation

The concept of linear approximation just follows from the equation of the tangent line. i.e., The equation of the tangent line of a function y = f(x) at a point (x0, y0) can be used to approximate the value of the function at any point that is very close to (x0, y0). We can understand this from the example below.

Example of Tangent Line Approximation

Use the tangent line approximation to find the approximate value of ∛8.1.

Solution

We know that ∛8 = 2 and 8.1 very close to 8.

So we assume the function to be f(x) = ∛x and the point where the tangent is drawn to be x0 = 8.

Then (x0, y0) = (8, ∛8) = (8, 2).

The derivative of the function is f '(x) = (1/3) x-2/3

The slope of the tangent is, m = (f '(x))₍₈, ₂) = (1/3) (8)-2/3 = (1/3) (23)-2/3 = (1/3) (1/4) = 1/12

The equation of the tangent line is, y - y0 = m (x - x0)

y - 2 = (1/12) (x - 8)

y = x/12 - 2/3 + 2

y = x/12 + 4/3

Substituting y = f(x) here,

f(x) = x/12 + 4/3

Now, the approximate value of ∛8.1 can be obtained by substituting x = 8.1 here. Thus,

f(8.1) ≈ (8.1)/12 + 4/3

∛8.1 ≈ 2.008

We can check this with the calculator by finding the cube root of 8.1 and we can see it to be 2.008. This is how the tangent line approximation works.

Tangent Line Equation of Parametric Curve

Sometimes the function of the curve may not be given in the form y = f(x), instead, it might be represented in the parametric form. Let us see how to find the equation of a tangent line of a parametric curve in both 2D and 3D.

Tangent Line of Parametric Curve in 2D

If the curve in 2D is represented by the parametric equations x = x(t) and y = y(t), then the equation of the tangent line at t = a is found using the following steps:

  • Find the point at which the tangent is drawn, (x0, y0) by substituting t = a in the given parametric equations. i.e., (x0, y0) = (x(a), y(a)).
  • Find the derivative of the function using (dy/dt) / (dx/dt).
  • Find the slope of the tangent (m) by substituting either t = a in the above derivative.
  • Find the equation of the tangent line using y - y0 = m (x - x0).

Tangent Line of Parametric Curve in 3D

Let the curve in 3D is defined by the parametric equations x = x(t), y = y(t), and z = z(t). Here are the steps to find the equation of the tangent line at a point t = t0.

  • Substitute t = a in each of the given equations to find the point (x0, y0, z0) at which the tangent is drawn. i.e., (x0, y0, z0) = (x(t0), y(t0), and z(t0))
  • Find the derivatives x'(t), y'(t), and z'(t).
  • Substitute t = t0 in each of these derivatives to find the direction ratios <a, b, c> of the line. i.e., <a, b, c> = <x'(t0), y'(t0), z'(t0)>
  • Find the equation of the tangent line using one of the following formulas: x = x0 + at, y = y0 + bt, z = z0 + ct [OR] (x - x0) / a = (y - y0) / b = (z - z0) / c

We can see examples of these formulas in the "Examples" section below.

Tangent Line of Polar Curve

If the function is defined by polar equation r = r(t), then the equation of the tangent line at t = a is found by using the following steps:

  • Find 'r' where r = r(a).
  • Find the point (x0, y0) where the tangent is drawn using (x0, y0) = (r cos a, r sin a).
  • Find dy/dx using the formula,\(\dfrac{d y}{d x}=\dfrac{\dfrac{d r}{d t} \sin (t)+r \cos (t)}{\dfrac{d r}{d t} \cos (t)-r \sin (t)}\).
  • Find the slope of the tangent using, m = (dy/dx)t = a.
  • Find the equation of the tangent line using y - y0 = m (x - x0).

Important Notes on Tangent Line:

  • The equation of tangent line of a curve y = f(x) at a point (x0, y0) is found using y - y0 = m (x - x0), where m = (f '(x))(x0, y0).
  • If θ is the angle made by the tangent line with the positive direction of the x-axis, then its slope is m = tan θ.
  • Normal line and tangent line drawn for a curve at a point are perpendicular to each other and hence the slope of the normal = (-1) / (slope of the tangent).
  • A curve y = f(x) has horizontal tangents at the points where f '(x) = 0 as horizontal tangents are parallel to x-axis.
  • A curve y = f(x) has vertical tangents at the points where f '(x) is undefined as horizontal tangents are parallel to y-axis.
  • The tangent line equation is used to find the approximate values of the function in the neighborhood of the point at which the tangent is drawn.

☛ Related Topics:

  • Tangent Line Calculator
  • Derivative Calculator
  • Calculus Calculator

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