B. Xy-2y-4x=0 Select One - Gauthmath

Trang chủ » B. Xy – 2y – 4x = 0 » B. Xy-2y-4x=0 Select One - Gauthmath

Có thể bạn quan tâm

Math Resources/Physics/

Question

a volume of 0.0024m3 of oil is heated in a pan for 7 min. The temperature of the oil increases from 20°C to 180°C, The density of the oil is 910kg/m3 the specific heat capacity of the oil is 2000J/(kg°C). Calculate the energy neede to increase the temperature of the oilSHOW LESS5

Solution

The energy needed to increase the temperature of the oil is 699840 Joules.

Step 1: Calculate the mass of the oil: Given volume of oil = 0.0024 m^3 Density of the oil = 910 kg/m^3 Using the formula: Density = Mass/Volume Mass = Density * Volume Mass = 910 kg/m^3 * 0.0024 m^3 Mass = 2.184 kg

Step 2: Calculate the temperature change: Initial temperature = 20°C Final temperature = 180°C Temperature change = Final temperature - Initial temperature Temperature change = 180°C - 20°C Temperature change = 160°C

Step 3: Calculate the energy needed to increase the temperature of the oil: Specific heat capacity of the oil = 2000 J/(kg°C) Energy = Mass * Specific heat capacity * Temperature change Energy = 2.184 kg * 2000 J/(kg°C) * 160°C Energy = 699840 J

Click to rate:11.3(53 votes)Search questionBy textBy image/screenshotDrop your file here orClick Hereto upload

Từ khóa » B. Xy – 2y – 4x = 0