C+7+3c=5c=+11 - Solution
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Solution for c+7+3c=5c=+11 equation:
c+7+3c=5c=+11 We move all terms to the left: c+7+3c-(5c)=0 We add all the numbers together, and all the variables -1c+7=0 We move all terms containing c to the left, all other terms to the right -c=-7 c=-7/-1 c=+7See similar equations:
| -12+2x+x^2=0 | | 1/2u=25 | | (2x×x)=210 | | 1.9+x=2.7 | | 27y=1 | | N+6=9x7 | | 2/3y-1/5(y-21/2)=51/3 | | h=15-4h | | 2(3x-2)-5=15-(x+3) | | 2(3x-2)-5=15-(x+3 | | 8^(x^2+2x-8)=64 | | a=7X4 | | 5(b-3)-2(b-1)=-6 | | X+(2x×x)=210 | | a=7.4 | | 44=4v | | 3g=-2(4g+11) | | R=r/12 | | 0.3/x=0.1 | | v=18+6+4 | | 2(-7)=d | | v=13+45 | | V=13+9x5 | | 2(-7)+7=y | | 21/x=8 | | 2(-14)+7=y | | 20=y/9 | | 3x+49=70 | | 2-x(4-5x)=6 | | xx67=17 | | -20x+12=Y | | 3g-8g+4=-5g |
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