Algebra InputsTrigonometry InputsCalculus InputsMatrix Inputs Basic algebra trigonometry calculus statistics matrices CharactersEvaluate c\left(29-3c\right)View solution stepsSolution Steps 3 c ( 5 + c ) - 2 c ( 3 c - 7 ) Use the distributive property to multiply 3c by 5+c. 15c+3c^{2}-2c\left(3c-7\right) Use the distributive property to multiply -2c by 3c-7. 15c+3c^{2}-6c^{2}+14c Combine 3c^{2} and -6c^{2} to get -3c^{2}. 15c-3c^{2}+14c Combine 15c and 14c to get 29c. 29c-3c^{2} Expand 29c-3c^{2}View solution stepsSolution Steps 3 c ( 5 + c ) - 2 c ( 3 c - 7 ) Use the distributive property to multiply 3c by 5+c. 15c+3c^{2}-2c\left(3c-7\right) Use the distributive property to multiply -2c by 3c-7. 15c+3c^{2}-6c^{2}+14c Combine 3c^{2} and -6c^{2} to get -3c^{2}. 15c-3c^{2}+14c Combine 15c and 14c to get 29c. 29c-3c^{2} QuizPolynomial 3 c ( 5 + c ) - 2 c ( 3 c - 7 )
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(-2,64)to(-76,-73)https://www.tiger-algebra.com/drill/(-2,64)to(-76,-73)/ Finding the distance, midpoint, slope, equation and the x y-intercepts of a line passing between the two points p1 (-2,64) and p2 (-76,-73)The distance (d) between two points (x1,y1) and (x2,y2) is ... How do you solve \displaystyle-{272}={8}-{7}{\left({5}{n}+{5}\right)} ?https://socratic.org/questions/how-do-you-solve-272-8-7-5n-5 \displaystyle{n}={7} Here's how I did it: Explanation: \displaystyle-{272}={8}-{7}{\left({5}{n}+{5}\right)} First, let's subtract \displaystyle{8} from both sides of the equation: \displaystyle-{280}=-{7}{\left({5}{n}+{5}\right)} ... 2c3+3c2-2c-3https://www.tiger-algebra.com/drill/2c3_3c2-2c-3/ 2c3+3c2-2c-3 Final result : (c + 1) • (c - 1) • (2c + 3) Reformatting the input : Changes made to your input should not affect the solution: (1): "c2" was replaced by "c^2". 1 more similar ... (5c-d)(2c)+(5c-d)(4d)https://www.tiger-algebra.com/drill/(5c-d)(2c)_(5c-d)(4d)/ (5c-d)(2c)+(5c-d)(4d) Final result : 2 • (5c - d) • (c + 2d) Step by step solution : Step 1 :Equation at the end of step 1 : ((5c - d) • 2c) + 4d • (5c - d) Step 2 :Equation at the end of step ... How do you solve \displaystyle{5}{c}+{3}={15}+{4}{c}-{2} ?https://socratic.org/questions/how-do-you-solve-5c-3-15-4c-2 See the entire solution process below: Explanation: First, combine the constants on the right side of the equation: \displaystyle{5}{c}+{3}={15}+{4}{c}-{2} \displaystyle{5}{c}+{3}={15}-{2}+{4}{c} ... 5c-2=3c(24c)https://www.tiger-algebra.com/drill/5c-2=3c(24c)/ 5c-2=3c(24c) Two solutions were found : c =(-5-√-551)/-144=(5+i√ 551 )/144= 0.0347-0.1630i c =(-5+√-551)/-144=(5-i√ 551 )/144= 0.0347+0.1630i Rearrange: Rearrange the equation by subtracting ...More Items
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CopyCopied to clipboard15c+3c^{2}-2c\left(3c-7\right) Use the distributive property to multiply 3c by 5+c.15c+3c^{2}-6c^{2}+14c Use the distributive property to multiply -2c by 3c-7.15c-3c^{2}+14c Combine 3c^{2} and -6c^{2} to get -3c^{2}.29c-3c^{2} Combine 15c and 14c to get 29c.15c+3c^{2}-2c\left(3c-7\right) Use the distributive property to multiply 3c by 5+c.15c+3c^{2}-6c^{2}+14c Use the distributive property to multiply -2c by 3c-7.15c-3c^{2}+14c Combine 3c^{2} and -6c^{2} to get -3c^{2}.29c-3c^{2} Combine 15c and 14c to get 29c.
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Quadratic equation { x } ^ { 2 } - 4 x - 5 = 0Trigonometry 4 \sin \theta \cos \theta = 2 \sin \thetaLinear equation y = 3x + 4Arithmetic 699 * 533Matrix \left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]Simultaneous equation \left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.Differentiation \frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }Integration \int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d xLimits \lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}Back to top
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View solution stepsSolution Steps 3 c ( 5 + c ) - 2 c ( 3 c - 7 ) Use the distributive property to multiply 3c by 5+c. 15c+3c^{2}-2c\left(3c-7\right) Use the distributive property to multiply -2c by 3c-7. 15c+3c^{2}-6c^{2}+14c Combine 3c^{2} and -6c^{2} to get -3c^{2}. 15c-3c^{2}+14c Combine 15c and 14c to get 29c. 29c-3c^{2} Expand 29c-3c^{2}
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