C10H15NO + H2O = C10H17NO2 - Chemical Equation Balancer
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Balanced Chemical Equation
C10H15NO + H2O → C10H17NO2 Reaction Info Balance Another Equation Step-by-Step Solution Practice BalancingReaction Information Disclaimer
Word Equation
Hordenine + Water = Methyprylon
C10H15NO + H2O = C10H17NO2 is a Synthesis reaction where one mole of Hordenine [C10H15NO] and one mole of Water [H2O] combine to form one mole of Methyprylon [C10H17NO2]
Reaction Type
Synthesis
Reactants
Hordenine - C10H15NO
Dimethyltyramine P-(2-Dimethylaminoethyl)Phenol N,N-Dimethyltyramine 4-[2-(Dimethylamino)Ethyl]Phenol C10H15NO Molar Mass C10H15NO Oxidation NumberWater - H2O
Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number
Products
Methyprylon - C10H17NO2
Methyprolon Metiprilon Methprylon Methyprylone C10H17NO2 Molar Mass C10H17NO2 Oxidation Number
Reaction Expressions
Equilibrium Constant & Reaction Quotient Kc or Q = ( [C10H17NO2] ) / ( [C10H15NO] [H2O] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[C10H15NO] / Δt) = -(Δ[H2O] / Δt) = (Δ[C10H17NO2] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜Instructions
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Examples
- Hordenine + Water = Methyprylon
- C10H15NO + H2O + C7C8 = C10H15N + H2O
- C10H15NO + H2O + Cl2 = C10H15N + HOCl
- C10H15NO + H2O + H3PO2 + I2 = C10H15N + HI + H3PO3
- C10H15NO + H2O + H3PO4 + I2 = C10H15N + HI + H3PO3
- C10H15NO + H2O + Na = C10H15N + NaOH
- C10H15NO + H2O + NaOH + C7H8 = C10H15N + NaOH
- C10H15NO + H2O + NaOH = C10H15N + NaOH
- C10H15NO + H2O + S = C10H15N + H2SO4
- KHCO3 + Al2(SO4)3 = K2O4S + Al(OH)3 + CO2
- SO2 + NO3 = SO3 + NO2
- K2Cr2O7 + FeSO4 + H2SO4 = Fe2(SO4)3 + K2SO4 + H2O + CrSO4
- C12H7NO3 + HCl = C12H9Cl2NO3
- Recently Balanced Equations
Balance C10H15NO + H2O = C10H17NO2 Using the Algebraic Method
To balance the equation C10H15NO + H2O = C10H17NO2 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.
Step 1: Label Each Compound With a Variable
Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.
a C10H15NO + b H2O = c C10H17NO2
Step 2: Create a System of Equations
Create an equation for each element (C, H, N, O) where each term represents the number of atoms of the element in each reactant or product.
C: 10a + 0b = 10c H: 15a + 2b = 17c N: 1a + 0b = 1c O: 1a + 1b = 2cStep 3: Solve For All Variables
Use substitution, Gaussian elimination, or a calculator to solve for each variable.
Using Substitution or Elimination- 10a - 10c = 0
- 15a + 2b - 17c = 0
- 1a - 1c = 0
- 1a + 1b - 2c = 0
Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:
[ 10 0 -10 0] [ 15 2 -17 0] [ 1 0 -1 0] [ 1 1 -2 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-StepSimplify the result to get the lowest, whole integer values.
- a = 1 (C10H15NO)
- b = 1 (H2O)
- c = 1 (C10H17NO2)
Step 4: Substitute Coefficients and Verify Result
Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.
C10H15NO + H2O = C10H17NO2Reactants | Products | ||
---|---|---|---|
C | 10 | 10 | ✔️ |
H | 17 | 17 | ✔️ |
N | 1 | 1 | ✔️ |
O | 2 | 2 | ✔️ |
Balance C10H15NO + H2O = C10H17NO2 Using Inspection
The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C10H15NO + H2O = C10H17NO2 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.
Step 1: Count the number of each element on the left and right hand sides
Reactants (Left Hand Side) | Products (Right Hand Side) | |||||
---|---|---|---|---|---|---|
Reactants | Products | |||||
C10H15NO | H2O | Total | C10H17NO2 | Total | ||
C | 10 | 10 | 10 | 10 | ✔️ | |
H | 15 | 2 | 17 | 17 | 17 | ✔️ |
N | 1 | 1 | 1 | 1 | ✔️ | |
O | 1 | 1 | 2 | 2 | 2 | ✔️ |
The number of atoms of each element on both sides of C10H15NO + H2O = C10H17NO2 is equal which means that the equation is already balanced and no additional work is needed.
Practice Balancing
C10H15NO - + + H2O - + = C10H17NO2 - +Reactants | Products | ||
---|---|---|---|
C | 10 | 10 | ✔️ |
H | 17 | 17 | ✔️ |
N | 1 | 1 | ✔️ |
O | 2 | 2 | ✔️ |
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