C10H15NO + H2O = OH{-} + C10H15NOH{+} - ChemicalAid

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Balanced Chemical Equation

C10H15NO + H2O → OH- + C10H15NOH+ Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Hordenine + Water = Hydroxide Ion + Edrophonium

C10H15NO + H2O = OH{-} + C10H15NOH{+} is a Double Displacement (Metathesis) reaction where one mole of Hordenine [C10H15NO] and one mole of Water [H2O] react to form one mole of Hydroxide Ion [OH-] and one mole of Edrophonium [C10H15NOH+]

Reaction Type

Double Displacement (Metathesis)

Reactants

• Hordenine - C10H15NO

  Dimethyltyramine P-(2-Dimethylaminoethyl)Phenol N,N-Dimethyltyramine 4-[2-(Dimethylamino)Ethyl]Phenol C10H15NO Molar Mass C10H15NO Oxidation Number

• Water - H2O

  Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number

Products

• Hydroxide Ion - OH-

  OH{-} Molar Mass OH{-} Oxidation Number

• Edrophonium - C10H15NOH+

  Edr Edrophonium Ion Tensilon® Enlon®

Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [OH-] [C10H15NOH+] ) / ( [C10H15NO] [H2O] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -(Δ[C10H15NO] / Δt) = -(Δ[H2O] / Δt) = (Δ[OH-] / Δt) = (Δ[C10H15NOH+] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

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To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

• Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
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How To Balance Equations

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Examples

• Hordenine + Water = Hydroxide Ion + Edrophonium
• C10H15NO + H2O + C7C8 = C10H15N + H2O
• C10H15NO + H2O + Cl2 = C10H15N + HOCl
• C10H15NO + H2O + H3PO2 + I2 = C10H15N + HI + H3PO3
• C10H15NO + H2O + H3PO4 + I2 = C10H15N + HI + H3PO3
• C10H15NO + H2O + Na = C10H15N + NaOH
• C10H15NO + H2O + NaOH + C7H8 = C10H15N + NaOH
• C10H15NO + H2O + NaOH = C10H15N + NaOH
• C10H15NO + H2O + S = C10H15N + H2SO4
• KHCO3 + Al2(SO4)3 = K2O4S + Al(OH)3 + CO2
• K2Cr2O7 + FeSO4 + H2SO4 = Fe2(SO4)3 + K2SO4 + H2O + CrSO4
• SO2 + NO3 = SO3 + NO2
• Hg + F2 = F2Hg
• Recently Balanced Equations

Balance C10H15NO + H2O = OH{-} + C10H15NOH{+} Using the Algebraic Method

To balance the equation C10H15NO + H2O = OH{-} + C10H15NOH{+} using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C10H15NO + b H2O = c OH- + d C10H15NOH+

Step 2: Create a System of Equations

Create an equation for each element (C, H, N, O) where each term represents the number of atoms of the element in each reactant or product.

C: 10a + 0b = 0c + 10d H: 15a + 2b = 1c + 16d N: 1a + 0b = 0c + 1d O: 1a + 1b = 1c + 1d

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination

• 10a - 10d = 0
• 15a + 2b - 1c - 16d = 0
• 1a - 1d = 0
• 1a + 1b - 1c - 1d = 0

Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 10 0 0 -10 0] [ 15 2 -1 -16 0] [ 1 0 0 -1 0] [ 1 1 -1 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

• a = 1 (C10H15NO)
• b = 1 (H2O)
• c = 1 (OH{-})
• d = 1 (C10H15NOH{+})

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

C10H15NO + H2O = OH- + C10H15NOH+

Reactants	Products
C	10	10	✔️
H	17	17	✔️
N	1	1	✔️
O	2	2	✔️

Since there is an equal number of each element in the reactants and products of C10H15NO + H2O = OH{-} + C10H15NOH{+}, the equation is balanced.

Balance C10H15NO + H2O = OH{-} + C10H15NOH{+} Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C10H15NO + H2O = OH{-} + C10H15NOH{+} must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)			Products (Right Hand Side)
Reactants	Products
C10H15NO	H2O	Total	OH-	C10H15NOH+	Total
C	10	10	10	10	✔️
H	15	2	17	1	16	17	✔️
N	1	1	1	1	✔️
O	1	1	2	1	1	2	✔️

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

C10H15NO + H2O = OH- + C10H15NOH+

Practice Balancing

C10H15NO - + + H2O - + = OH- - + + C10H15NOH+ - +

Reactants	Products
C	10	10	✔️
H	17	17	✔️
N	1	1	✔️
O	2	2	✔️

Hint: The sum of the balanced coefficients is 4. See Step-By-Step Solution

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