C10H15NO + NaOH + C8H8O3 = C10H15N + NaHCO3 + H2 ...

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Balanced Chemical Equation

13C10H15NO + 8NaOH + C8H8O3 → 13C10H15N + 8NaHCO3 + 4H2 Reaction Info Balance Another Equation Step-by-Step Solution Practice Balancing

Reaction Information Disclaimer

Word Equation

Hordenine + Sodium Hydroxide + Vanillin = D-Methamphetamine + Sodium Bicarbonate + Dihydrogen

Thirteen moles of Hordenine [C10H15NO], eight moles of Sodium Hydroxide [NaOH] and one mole of Vanillin [C8H8O3] react to form thirteen moles of D-Methamphetamine [C10H15N], eight moles of Sodium Bicarbonate [NaHCO3] and four moles of Dihydrogen [H2]

Reactants

  • Hordenine - C10H15NO

    Dimethyltyramine P-(2-Dimethylaminoethyl)Phenol N,N-Dimethyltyramine 4-[2-(Dimethylamino)Ethyl]Phenol C10H15NO Molar Mass C10H15NO Oxidation Number

  • Sodium Hydroxide - NaOH

    White Caustic Naoh Sodium Hydrate Soda Lye Lye Caustic Soda NaOH Molar Mass NaOH Oxidation Number

  • Vanillin - C8H8O3

    Vanilla Oleoresin (Vanilla Spp) Vanillin [Usan] Vanilla Oleoresin 4-Hydroxy 3-Methoxybenzaldehyde Vanillin (Natural) Oleo-Resins Vanilla-Bean Oleo-Resins Vanilla Zimco C8H8O3 Molar Mass C8H8O3 Oxidation Number

Products

  • D-Methamphetamine - C10H15N

    Metamfetamine S-Methamphetamine Methamphetaminum Methamphetamine Metanfetamina Metamfetaminum Métamfétamine Methyl-Beta-Phenylisopropylamine C10H15N Molar Mass C10H15N Oxidation Number

  • Sodium Bicarbonate - NaHCO3

    Citrosodina Neut Bicarbonate Of Soda Sodium Hydrogen Carbonate E500 Carbonic Acid Monosodium Salt Sodium Acid Carbonate E 500 NaHCO3 Molar Mass NaHCO3 Oxidation Number

  • Dihydrogen - H2

    Molecular Hydrogen Hydrogen Molecule Hydrogen Hydrogen Gas Molecular Hydrogen Gas H₂ H2 Molar Mass H2 Bond Polarity H2 Oxidation Number
Show Chemical Structure Image

Reaction Expressions

Equilibrium Constant & Reaction Quotient Kc or Q = ( [C10H15N]13 [NaHCO3]8 [H2]4 ) / ( [C10H15NO]13 [NaOH]8 [C8H8O3] )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/13 * (Δ[C10H15NO] / Δt) = -1/8 * (Δ[NaOH] / Δt) = -(Δ[C8H8O3] / Δt) = 1/13 * (Δ[C10H15N] / Δt) = 1/8 * (Δ[NaHCO3] / Δt) = 1/4 * (Δ[H2] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

  • Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
  • Ionic charges are not yet supported and will be ignored.
  • Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
  • Compound states [like (s) (aq) or (g)] are not required.
  • You can use parenthesis () or brackets [].

How To Balance Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

Examples

  • Hordenine + Sodium Hydroxide + Vanillin = D-Methamphetamine + Sodium Bicarbonate + Dihydrogen
  • C10H15NO + NaOH + C8H8O3 = C10H15N + CHNaO3 + H2
  • NaMnO4 + SO2 + H2O = NaSO4 + MnSO4 + H2SO3
  • KAl(SO4)2 + K2S + H2O = Al(OH)3 + H2S + K2O4S
  • Ba(NO2)2 + MnO2 + H2SO4 = MnSO4 + BaSO4 + HNO3 + H2O
  • ZnCl2 + MgO = ZnO + MgCl2
  • Al + Na2CO3 = Na + C3Al2O9
  • BaCl2 + Li = ClLi + Ba
  • Fe2(SO4)3 + BaSO4 = BaSO4 + Fe2(SO4)3
  • PBCO3 + HNO3 = PB(NO3)2 + CO2 + H2O
  • C6H4(COOC2H5)2 + H2O = C6H4(COOH)2 + C2H5OH
  • NaOH + ZnO = Na2O + H2O2Zn
  • C2H2 + Ag2O + NH3 = Ag2C2 + H2O + NH3
  • Recently Balanced Equations

Balance C10H15NO + NaOH + C8H8O3 = C10H15N + NaHCO3 + H2 Using the Algebraic Method

To balance the equation C10H15NO + NaOH + C8H8O3 = C10H15N + NaHCO3 + H2 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.

a C10H15NO + b NaOH + c C8H8O3 = d C10H15N + f NaHCO3 + g H2

Step 2: Create a System of Equations

Create an equation for each element (C, H, N, O, Na) where each term represents the number of atoms of the element in each reactant or product.

C: 10a + 0b + 8c = 10d + 1f + 0g H: 15a + 1b + 8c = 15d + 1f + 2g N: 1a + 0b + 0c = 1d + 0f + 0g O: 1a + 1b + 3c = 0d + 3f + 0g Na: 0a + 1b + 0c = 0d + 1f + 0g

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.

Using Substitution or Elimination
  • 10a + 8c - 10d - 1f = 0
  • 15a + 1b + 8c - 15d - 1f - 2g = 0
  • 1a - 1d = 0
  • 1a + 1b + 3c - 3f = 0
  • 1b - 1f = 0
Using Linear Systems / Algebra

Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 10 0 8 -10 -1 0 0] [ 15 1 8 -15 -1 -2 0] [ 1 0 0 -1 0 0 0] [ 1 1 3 0 -3 0 0] [ 0 1 0 0 -1 0 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-Step

Simplify the result to get the lowest, whole integer values.

  • a = 13 (C10H15NO)
  • b = 8 (NaOH)
  • c = 1 (C8H8O3)
  • d = 13 (C10H15N)
  • f = 8 (NaHCO3)
  • g = 4 (H2)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.

13 C10H15NO + 8 NaOH + C8H8O3 = 13 C10H15N + 8 NaHCO3 + 4 H2
Reactants Products
C138138✔️
H211211✔️
N1313✔️
O2424✔️
Na88✔️
Since there is an equal number of each element in the reactants and products of 13C10H15NO + 8NaOH + C8H8O3 = 13C10H15N + 8NaHCO3 + 4H2, the equation is balanced.

Balance C10H15NO + NaOH + C8H8O3 = C10H15N + NaHCO3 + H2 Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in C10H15NO + NaOH + C8H8O3 = C10H15N + NaHCO3 + H2 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side)Products (Right Hand Side)
ReactantsProducts
C10H15NONaOHC8H8O3TotalC10H15NNaHCO3H2Total
C1081810111❌
H151824151218❌
N1111✔️
O113533❌
Na1111✔️

Step 2: Multiply coefficients for compounds to balance out each element

For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.

  1. C is not balanced. Add 7 molecules of NaHCO3 to the product (right-hand) side to balance Carbon: C10H15NO + NaOH + C8H8O3 = C10H15N + 8NaHCO3 + H2
    ReactantsProducts
    C1818✔️
    H2425❌
    N11✔️
    O524❌
    Na18❌
  2. H is not balanced. Add 1 molecule of NaOH to the reactant (left-hand) side to balance Hydrogen: C10H15NO + 2NaOH + C8H8O3 = C10H15N + 8NaHCO3 + H2
    ReactantsProducts
    C1818✔️
    H2525✔️
    N11✔️
    O624❌
    Na28❌
  3. O is not balanced. Add 12 molecules of C10H15NO to the reactant (left-hand) side to balance Oxygen: 13C10H15NO + 2NaOH + C8H8O3 = C10H15N + 8NaHCO3 + H2
    ReactantsProducts
    C13818❌
    H20525❌
    N131❌
    O1824❌
    Na28❌
  4. C is not balanced. Add 12 molecules of C10H15N to the product (right-hand) side to balance Carbon: 13C10H15NO + 2NaOH + C8H8O3 = 13C10H15N + 8NaHCO3 + H2
    ReactantsProducts
    C138138✔️
    H205205✔️
    N1313✔️
    O1824❌
    Na28❌
  5. O is not balanced. Add 6 molecules of NaOH to the reactant (left-hand) side to balance Oxygen: 13C10H15NO + 8NaOH + C8H8O3 = 13C10H15N + 8NaHCO3 + H2
    ReactantsProducts
    C138138✔️
    H211205❌
    N1313✔️
    O2424✔️
    Na88✔️
  6. H is not balanced. Add 3 molecules of H2 to the product (right-hand) side to balance Hydrogen: 13C10H15NO + 8NaOH + C8H8O3 = 13C10H15N + 8NaHCO3 + 4H2
    ReactantsProducts
    C138138✔️
    H211211✔️
    N1313✔️
    O2424✔️
    Na88✔️

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

13C10H15NO + 8NaOH + C8H8O3 = 13C10H15N + 8NaHCO3 + 4H2

Practice Balancing

C10H15NO - + + NaOH - + + C8H8O3 - + = C10H15N - + + NaHCO3 - + + H2 - +
ReactantsProducts
C1811❌
H2418❌
N11✔️
O53❌
Na11✔️
Hint: The sum of the balanced coefficients is 47. See Step-By-Step Solution

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