NaOH + C10H15NO = NaNOH15C10OH - Chemical Equation ...
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Balanced Chemical Equation
NaOH + C10H15NO → NaNOH15C10OHWarning: One of the compounds in NaOH + C10H15NO = NaNOH15C10OH is unrecognized. Verify 'NaNOH15C10OH' is entered correctly.
Reaction Info Balance Another Equation Step-by-Step Solution Practice BalancingReaction Information Disclaimer
NaOH+C10H15NO=NaNOH15C10OHReaction Type
Synthesis
Reactants
Sodium Hydroxide - NaOH
White Caustic Naoh Sodium Hydrate Soda Lye Lye Caustic Soda NaOH Molar Mass NaOH Oxidation NumberHordenine - C10H15NO
Dimethyltyramine P-(2-Dimethylaminoethyl)Phenol N,N-Dimethyltyramine 4-[2-(Dimethylamino)Ethyl]Phenol C10H15NO Molar Mass C10H15NO Oxidation Number
Products
- NaNOH15C10OH
Instructions
To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.
- Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
- Ionic charges are not yet supported and will be ignored.
- Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
- Compound states [like (s) (aq) or (g)] are not required.
- You can use parenthesis () or brackets [].
How To Balance Equations
Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.
Read our article on how to balance chemical equations or ask for help in our chat.
Examples
- NaNO3 + SrCl2 = Sr(NO3)2 + NaCl
- KCl + HNO3 = Cl + NO2 + H2O + KNO3
- KHCO3 + Al2(SO4)3 = K2O4S + Al(OH)3 + CO2
- SO2 + NO3 = SO3 + NO2
- Hg + F2 = F2Hg
- Na2CO3 + HBr = BrNa + H2O + CO2
- K2Cr2O7 + FeSO4 + H2SO4 = Fe2(SO4)3 + K2SO4 + H2O + CrSO4
- MgH2 + O2 = MgO + H2
- CaCO3 + ZnO = CaO + CO3Zn
- KI(Ac) + Pb(NO3)2(Ac) = PbI2(Ac) + KNO3(Ac)
- KF + H2SO4 = HKO4S + FH
- C12H7NO3 + HCl = C12H9Cl2NO3
- Recently Balanced Equations
Balance NaOH + C10H15NO = NaNOH15C10OH Using the Algebraic Method
To balance the equation NaOH + C10H15NO = NaNOH15C10OH using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.
Step 1: Label Each Compound With a Variable
Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.
a NaOH + b C10H15NO = c NaNOH15C10OH
Step 2: Create a System of Equations
Create an equation for each element (Na, O, H, C, N) where each term represents the number of atoms of the element in each reactant or product.
Na: 1a + 0b = 1c O: 1a + 1b = 2c H: 1a + 15b = 16c C: 0a + 10b = 10c N: 0a + 1b = 1cStep 3: Solve For All Variables
Use substitution, Gaussian elimination, or a calculator to solve for each variable.
Using Substitution or Elimination- 1a - 1c = 0
- 1a + 1b - 2c = 0
- 1a + 15b - 16c = 0
- 10b - 10c = 0
- 1b - 1c = 0
Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:
[ 1 0 -1 0] [ 1 1 -2 0] [ 1 15 -16 0] [ 0 10 -10 0] [ 0 1 -1 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-StepSimplify the result to get the lowest, whole integer values.
- a = 1 (NaOH)
- b = 1 (C10H15NO)
- c = 1 (NaNOH15C10OH)
Step 4: Substitute Coefficients and Verify Result
Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.
NaOH + C10H15NO = NaNOH15C10OHReactants | Products | ||
---|---|---|---|
Na | 1 | 1 | ✔️ |
O | 2 | 2 | ✔️ |
H | 16 | 16 | ✔️ |
C | 10 | 10 | ✔️ |
N | 1 | 1 | ✔️ |
Balance NaOH + C10H15NO = NaNOH15C10OH Using Inspection
The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in NaOH + C10H15NO = NaNOH15C10OH must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.
Step 1: Count the number of each element on the left and right hand sides
Reactants (Left Hand Side) | Products (Right Hand Side) | |||||
---|---|---|---|---|---|---|
Reactants | Products | |||||
NaOH | C10H15NO | Total | NaNOH15C10OH | Total | ||
Na | 1 | 1 | 1 | 1 | ✔️ | |
O | 1 | 1 | 2 | 2 | 2 | ✔️ |
H | 1 | 15 | 16 | 16 | 16 | ✔️ |
C | 10 | 10 | 10 | 10 | ✔️ | |
N | 1 | 1 | 1 | 1 | ✔️ |
The number of atoms of each element on both sides of NaOH + C10H15NO = NaNOH15C10OH is equal which means that the equation is already balanced and no additional work is needed.
Practice Balancing
NaOH - + + C10H15NO - + = NaNOH15C10OH - +Reactants | Products | ||
---|---|---|---|
Na | 1 | 1 | ✔️ |
O | 2 | 2 | ✔️ |
H | 16 | 16 | ✔️ |
C | 10 | 10 | ✔️ |
N | 1 | 1 | ✔️ |
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