Explain The Geometry Of Cu(Nh3)4 2+ On The Basis Of Hybridisation ...

English0Maharashtra State BoardHSC Science (General) 12th Standard Board ExamQuestion PapersQuestion Papers328Textbook Solutions13151MCQ Online Mock Tests73Important Solutions9039Concept Notes & Videos456Time Tables32SyllabusExplain the Geometry of Cu(Nh3)4 2+ on the Basis of Hybridisation At. No. Cu = 29 - Chemistry

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Question

Explain the geometry of [Cu(NH3)4]2+ on the basis of hybridisation [ At. No. Cu = 29 ].

Answer in Brief

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SolutionShow Solution

1. The oxidation state of Cu in [Cu(NH3)4]2+ is + 2. The electronic configuration of Cu2+ is 3d94s0.
2. dsp2 hybridisation of one d, one s and two p orbitals result in square planar geometry.
3. Coordinate bonds are formed by overlap of metal dsp2 hybrid orbitals.
4. Due to presence of one unpaired electron, [ Cu(NH3)4 ]2+ is paramagnetic. The magnetic moment, μ is 1.73 B.M.

shaalaa.comConcept of Group 15 Elements Report Error Is there an error in this question or solution?Q 5.iQ 4.viiQ 5.ii2017-2018 (July) Set 1

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