16 thg 6, 2019 · In [Ni(NH3)4]2+ , nickel is present in +2 oxidation state {Ni = 3d8 4s0}. NH3 is a weak ligand, so it can not pair the upaired electrons.
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(1) Number of unpaired electrons=2 ∴μs=22(2+2) =2.83BM Since the hybridisation is sp3, the geometry of the molecule is tetrahedral. · Valence Bond Theory.
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magnetic moment · oxidation number of Ni · geometry · EAN (Effective Atomic Number) · Ni(CO)4, Ni,d10,EAN=28+8=36,sp3 hybridization and tetrahedral geometry. Here, ...
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Ni is in the oxidation state of +2. So Config. of Ni2+ - 4s(2) 3d(8). Now NH3 is a strong field ligand, it will compress all 8 electrons ...
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Transcribed image text: 57. The transistion metal complex ion, [Ni(NH3)4]2+, has an square planar geometry, is diamagnetic, and has a formation constant, ...
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Explanation:[Ni(NH3)4]²+ is paramagnetic. Reason -Electronic configuration of Ni =[Ar] 4s² 3d^8Now, O.N. of Central metal =x + 0×4 = 2x ...
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Phase Label(s): Ni[SCN]2[NH3]4| Classification by Properties: - | Springer & Material Phases Data System 2016.
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Ni(CO)4 and [Ni(NH3)4]2+ do not differ is. (A):magnetic moment; (B):oxidation number of Ni; (C):geometry; (D):EAN. Best Answer. Correct Answer:.
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Hey...Hybridization in Ni(NH3)4^2 is "dsp3"
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The compound crystallizes in the triclinic space group P-1 with the unit cell parameters: a = 11.0856(13) Å, b = 15.242(2) Å, c = 21.232(3) Å, α = 90.158(4)°, β ...
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The oxidation state of Cu in [Cu(NH3)4]2+ is + 2. · dsp2 hybridisation of one d, one s and two p orbitals result in square planar geometry. · Coordinate bonds are ...
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Ni^(2+)(3d^(8)) ion undergoes sp^(3)- hybridisation and the hybrid orbitals are directed towards the four corners of tetrahedron.
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trigonal bipyramidal · tetrahedral · octahedral · square planar · 29Cu=1s2,2s22p6,3s23p63d10,4s1 Cu2+=[Ar]3d9,4s04p0. Hence, geometry of [Cu(NH3)4]2+ ion is ...
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As we know, Square planar geometry arises due to dsp2 hybridization. Thus, [Cu(NH3)4]2+ has a square planar geometry.
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