Explain The Type Hybridisation, Magnetic Property And Geometry For ...
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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIIChemistryMagnetic Moment ExamplesQuestionExplain the type hybridisation, magnetic property and geometry for [Ni(CN)4]2− and [Ni(NH3)4]2+ using VB theory.Open in AppSolutionVerified by Toppr
(1) Number of unpaired electrons=2∴μs=2√2(2+2)=2.83BMSince the hybridisation is sp3, the geometry of the molecule is tetrahedral.(2) Another possible geometry for the 4 coordinated complex is the square planar configuration involving dsp2 hybridisation.The ligand CN− is a powerful ligand. Hence if forces the unpaired electrons to pair up in d orbitals. Hence this complex ion does not contain unpaired electrons. It is diamagnetic.The geometry of the molecule is square planar.
Was this answer helpful?8Similar QuestionsQ1Explain the type hybridisation, magnetic property and geometry for [Ni(CN)4]2− and [Ni(NH3)4]2+ using VB theory.View SolutionQ2With the help of Valence bond theory account for hybridisation, geometry and magnetic property of [Ni(CN)4]2− complex ion [Z for Ni=28].View SolutionQ3Explain hybridisation, geometry and magnetic property of [Ni(CN)4]2− ion using Valence Bond Theory(VBT). [Atomic number of Ni is 28].View SolutionQ4With the help of Valence Bond Theory(VBT), explain hybridisation, geometry and magnetic property of [NiCl4]2−.View SolutionQ5Geometry, hybridisation and magnetic moment of the ions [Ni(CN)4]2−,[MnBr4]2− and [FeF6]4− respectively are:View SolutionTừ khóa » Ni(nh3)4 2+
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