Explain The Type Hybridisation, Magnetic Property And Geometry For ...

SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard XIIChemistryMagnetic Moment ExamplesQuestionExplain the type hybridisation, magnetic property and geometry for [Ni(CN)4]2 and [Ni(NH3)4]2+ using VB theory.Open in AppSolutionVerified by Toppr

(1) Number of unpaired electrons=2μs=22(2+2)=2.83BMSince the hybridisation is sp3, the geometry of the molecule is tetrahedral.(2) Another possible geometry for the 4 coordinated complex is the square planar configuration involving dsp2 hybridisation.The ligand CN is a powerful ligand. Hence if forces the unpaired electrons to pair up in d orbitals. Hence this complex ion does not contain unpaired electrons. It is diamagnetic.The geometry of the molecule is square planar.633645_607318_ans_06ef044c85004ad2aed957fc1fd1f24d.png

Was this answer helpful?8Similar QuestionsQ1Explain the type hybridisation, magnetic property and geometry for [Ni(CN)4]2 and [Ni(NH3)4]2+ using VB theory.View SolutionQ2With the help of Valence bond theory account for hybridisation, geometry and magnetic property of [Ni(CN)4]2 complex ion [Z for Ni=28].View SolutionQ3Explain hybridisation, geometry and magnetic property of [Ni(CN)4]2 ion using Valence Bond Theory(VBT). [Atomic number of Ni is 28].View SolutionQ4With the help of Valence Bond Theory(VBT), explain hybridisation, geometry and magnetic property of [NiCl4]2.View SolutionQ5Geometry, hybridisation and magnetic moment of the ions [Ni(CN)4]2,[MnBr4]2 and [FeF6]4 respectively are:View Solution

Từ khóa » Ni(nh3)4 2+