Factorize: 4a^2 - (4b^2 + 4bc + C^2) - Toppr

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SolveGuidesJoin / LoginUse appLogin0You visited us 0 times! Enjoying our articles? Unlock Full Access!Standard VIIIMathematicsQuestionFactorize:4a2−(4b2+4bc+c2).
  1. (a+b+c)(2a−2b+c)
  2. (a+2b+c)(2a−b−c)
  3. (a+b+c)(a−3b−c)
  4. (2a+2b+c)(2a−2b−c)
A(a+2b+c)(2a−b−c)B(a+b+c)(2a−2b+c)C(a+b+c)(a−3b−c)D(2a+2b+c)(2a−2b−c)Open in AppSolutionVerified by Toppr

4a2−(4b2+4bc+c2)=(2a)2−((2b)2+2(2b)(c)+c2)=(2a)2−(2b+c)2=(2a+2b+c)(2a−2b−c)

Was this answer helpful?15Similar QuestionsQ1Factorize : a2(b+c)2+b2(c+a)2+c2(a+b)+abc(a+b+c)+(a2+b2+c2)(bc+ca+ab)View SolutionQ2

Simplify:(a−2b+5c)(a−b)−(a−b−c)(2a+3c)+(6a+b)(2c−3a−5b)

View SolutionQ3State true or false(a−2b+5c)(a−b)−(a−b−c)(2a+3c)+(6a+b)(2c−3a−5b)=19ca−37ab−19a2View SolutionQ4Subtract a(2a+b−c)−b(a−2b+2c) from 3c(−2a+3b+c)View SolutionQ5∣∣ ∣∣a−b−c2a2a2bb−c−a2b2c2cc−a−b∣∣ ∣∣=View Solution

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