How Do You Factor By Grouping 4b^2+4bc+c^2-16? | Socratic

How do you factor by grouping #4b^2+4bc+c^2-16#? Algebra Polynomials and Factoring Factoring by Grouping

1 Answer

Alan P. Jun 23, 2015

#(2b+c+4)*(2b+c-4)#

Explanation:

#color(red)(4b^2+4bc+c^2) - color(blue)(16)# rewrite the frist 3 terms as a square #color(white)("XXXX")##color(red)((2b+c)^2) - color(blue)(4^2)# this is the difference of squares with a well-know factoring #color(white)("XXXX")##(2b+c+4)*(2b+c-4)#

Answer link

Related questions

• What is Factoring by Grouping?
• How do you factor by grouping four-term polynomials and trinomials?
• Why does factoring polynomials by grouping work?
• How do you factor #2x+2y+ax+ay#?
• How do you factor #3x^2+8x+4# by using the grouping method?
• How do you factor #6x^2-9x+10x-15#?
• How do you group and factor #4jk-8j^2+5k-10j#?
• What are the factors of #2m^3+3m^2+4m+6#?
• How do you factor quadratics by using the grouping method?
• How do you factor #x^4-2x^3+5x-10#?

See all questions in Factoring by Grouping

Impact of this question

3007 views around the world You can reuse this answer Creative Commons License