HNO3 + H2S = NO + S + H2O - Chemical Equation Balancer
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Balanced Chemical Equation
2HNO3 + 3H2S → 2NO + 3S + 4H2O Reaction Info Balance Another Equation Thermodynamics Step-by-Step Solution Practice BalancingReaction Information
Word Equation
Nitric Acid + Hydrogen Sulfide = Nitric Oxide (Radical) + Sulfur + Water
Two moles of Nitric Acid [HNO3] and three moles of Hydrogen Sulfide [H2S] react to form two moles of Nitric Oxide (Radical) [NO], three moles of Sulfur [S] and four moles of Water [H2O]
Reactants
Nitric Acid - HNO3
Hono2 Hydrogen Nitrate Engravers Acid Aqua Fortis Fuming Nitric Acid Spirit Of Niter HNO3 Molar Mass HNO3 Oxidation NumberHydrogen Sulfide - H2S
Hepatic Acid Stink Damp Hepatic Gas Sour Gas Hepatate Sulfur Hydride Sulfureted Hydrogen Hydrosulfurate H2S Molar Mass H2S Oxidation Number
Products
Nitric Oxide (Radical) - NO
Nitric Oxide Nitrosyl Hydride Nitrogen Protoxide Nitrogen Oxide Hydroxyamine Nitrosyl Radical Nitroxyl Nitroxide Radical NO Molar Mass NO Bond Polarity NO Oxidation NumberSulfur - S
Brimstone Element 16 Sulphur S Molar Mass S Oxidation NumberWater - H2O
Hydroxic Acid H₂O [Oh2] Aqua Pure Water Hydrogen Oxide Oxidane Dihydrogen Oxide H2O Molar Mass H2O Oxidation Number
Thermodynamics
Thermodynamics of the reaction can be calculated using a lookup table.
Choose Compound States HNO3 (l)HNO3 (g)HNO3 H2S (g)H2S NO (g)NO S (s rhombic)S (g)S (l)S H2O (g)H2O (l)H2O Change States Enthalpy CalculatorIs the Reaction Exothermic or Endothermic?
HNO3 (l) | 2 mol | -173.2176 kJ/mol | 346.4352 kJ |
---|---|---|---|
H2S (g) | 3 mol | -20.16688 kJ/mol | 60.50064 kJ |
NO (g) | 2 mol | 90.24888 kJ/mol | 180.49776 kJ |
S (s rhombic) | 3 mol | 0 kJ/mol | 0 kJ |
H2O (g) | 4 mol | -241.818464 kJ/mol | -967.273856 kJ |
ΣΔH°f(reactants) | -406.93584 kJ | ||
ΣΔH°f(products) | -786.776096 kJ | ||
ΔH°rxn | -379.840256 kJ |
Is the Reaction Exoentropic or Endoentropic?
ΔS = Sproducts - Sreactants. If ΔS < 0, it is exoentropic. If ΔS > 0, it is endoentropic.
HNO3 (l) | 2 mol | 155.60296 J/(mol K) | -311.20592 J/K |
---|---|---|---|
H2S (g) | 3 mol | 205.76912 J/(mol K) | -617.30736 J/K |
NO (g) | 2 mol | 210.651848 J/(mol K) | 421.303696 J/K |
S (s rhombic) | 3 mol | 31.92392 J/(mol K) | 95.77176 J/K |
H2O (g) | 4 mol | 188.715136 J/(mol K) | 754.860544 J/K |
ΣΔS°(reactants) | 928.51328 J/K | ||
ΣΔS°(products) | 1271.936 J/K | ||
ΔS°rxn | 343.42272 J/K |
Is the Reaction Exergonic or Endergonic?
ΔG = Gproducts - Greactants. If ΔG < 0, it is exergonic. If ΔG > 0, it is endergonic.
HNO3 (l) | 2 mol | -79.9144 kJ/mol | 159.8288 kJ |
---|---|---|---|
H2S (g) | 3 mol | -33.0536 kJ/mol | 99.1608 kJ |
NO (g) | 2 mol | 86.56696 kJ/mol | 173.13392 kJ |
S (s rhombic) | 3 mol | 0 kJ/mol | 0 kJ |
H2O (g) | 4 mol | -228.588656 kJ/mol | -914.354624 kJ |
ΣΔG°(reactants) | -258.9896 kJ | ||
ΣΔG°(products) | -741.220704 kJ | ||
ΔG°rxn | -482.231104 kJ |
Reaction Expressions
Equilibrium Constant & Reaction Quotient Kc or Q = ( [NO]2 [S]3 [H2O]4 ) / ( [HNO3]2 [H2S]3 )(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.) Rate of Reaction rate = -1/2 * (Δ[HNO3] / Δt) = -1/3 * (Δ[H2S] / Δt) = 1/2 * (Δ[NO] / Δt) = 1/3 * (Δ[S] / Δt) = 1/4 * (Δ[H2O] / Δt)(assuming constant volume in a closed system and no accumulation of intermediates or side products) Calculate Reaction Stoichiometry Calculate Limiting Reagent Chemical Equation Balancer 🛠️ Balance Equation ➜Instructions
To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.
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Examples
- Nitric Acid + Hydrogen Sulfide = Nitric Oxide (Radical) + Sulfur + Water
- HNO3 + H2S + H2O = NH4HSO4
- HNO3 + H2S = (NO2)H2O + S
- HNO3 + H2S = H20 + NO + S
- HNO3 + H2S = H2NO3 + HS
- HNO3 + H2S = H2O + H2SO4 + NO2
- HNO3 + H2S = H2O + N2 + S
- HNO3 + H2S = H2O + NO + H2O + S
- HNO3 + H2S = H2O + NO + H2SO4
- Ba(ClO3)2 + HBr = BaCl2 + Br2 + H2O
- NaHCO3 + Na2SiO3 = Na2CO3 + H2O3Si
- Al3O + H2O = Al3(OH)2
- CaCO3 + BaCl2 = CaCl2 + CBaO3
- Recently Balanced Equations
Balance HNO3 + H2S = NO + S + H2O Using the Algebraic Method
To balance the equation HNO3 + H2S = NO + S + H2O using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.
Step 1: Label Each Compound With a Variable
Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients.
a HNO3 + b H2S = c NO + d S + f H2O
Step 2: Create a System of Equations
Create an equation for each element (H, N, O, S) where each term represents the number of atoms of the element in each reactant or product.
H: 1a + 2b = 0c + 0d + 2f N: 1a + 0b = 1c + 0d + 0f O: 3a + 0b = 1c + 0d + 1f S: 0a + 1b = 0c + 1d + 0fStep 3: Solve For All Variables
Use substitution, Gaussian elimination, or a calculator to solve for each variable.
Using Substitution or Elimination- 1a + 2b - 2f = 0
- 1a - 1c = 0
- 3a - 1c - 1f = 0
- 1b - 1d = 0
Use your graphing calculator's rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:
[ 1 2 0 0 -2 0] [ 1 0 -1 0 0 0] [ 3 0 -1 0 -1 0] [ 0 1 0 -1 0 0] The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients. Convert to RREF and Solve Step-by-StepSimplify the result to get the lowest, whole integer values.
- a = 2 (HNO3)
- b = 3 (H2S)
- c = 2 (NO)
- d = 3 (S)
- f = 4 (H2O)
Step 4: Substitute Coefficients and Verify Result
Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.
2 HNO3 + 3 H2S = 2 NO + 3 S + 4 H2OReactants | Products | ||
---|---|---|---|
H | 8 | 8 | ✔️ |
N | 2 | 2 | ✔️ |
O | 6 | 6 | ✔️ |
S | 3 | 3 | ✔️ |
Balance HNO3 + H2S = NO + S + H2O Using Inspection
The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in HNO3 + H2S = NO + S + H2O must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.
Step 1: Count the number of each element on the left and right hand sides
Reactants (Left Hand Side) | Products (Right Hand Side) | |||||
---|---|---|---|---|---|---|
Reactants | Products | |||||
HNO3 | H2S | Total | NO | S | H2O | Total |
H | 1 | 2 | 3 | 2 | 2 | ❌ |
N | 1 | 1 | 1 | 1 | ✔️ | |
O | 3 | 3 | 1 | 1 | 2 | ❌ |
S | 1 | 1 | 1 | 1 | ✔️ |
Step 2: Multiply coefficients for compounds to balance out each element
For each element that is not equal, try to balance it by adding more of it to the side with less. Sometimes there may be multiple compounds with that element on one side, so you'll need to use your best judgement and be prepared to go back and try the other options.
- O is not balanced. Add 1 molecule of NO to the product (right-hand) side to balance Oxygen: HNO3 + H2S = 2NO + S + H2O
Reactants Products H 3 2 ❌ N 1 2 ❌ O 3 3 ✔️ S 1 1 ✔️ - N is not balanced. Add 1 molecule of HNO3 to the reactant (left-hand) side to balance Nitrogen: 2HNO3 + H2S = 2NO + S + H2O
Reactants Products H 4 2 ❌ N 2 2 ✔️ O 6 3 ❌ S 1 1 ✔️ - H is not balanced. Add 1 molecule of H2O to the product (right-hand) side to balance Hydrogen: 2HNO3 + H2S = 2NO + S + 2H2O
Reactants Products H 4 4 ✔️ N 2 2 ✔️ O 6 4 ❌ S 1 1 ✔️ - O is not balanced. Add 2 molecules of H2O to the product (right-hand) side to balance Oxygen: 2HNO3 + H2S = 2NO + S + 4H2O
Reactants Products H 4 8 ❌ N 2 2 ✔️ O 6 6 ✔️ S 1 1 ✔️ - H is not balanced. Add 2 molecules of H2S to the reactant (left-hand) side to balance Hydrogen: 2HNO3 + 3H2S = 2NO + S + 4H2O
Reactants Products H 8 8 ✔️ N 2 2 ✔️ O 6 6 ✔️ S 3 1 ❌ - S is not balanced. Add 2 molecules of S to the product (right-hand) side to balance Sulfur: 2HNO3 + 3H2S = 2NO + 3S + 4H2O
Reactants Products H 8 8 ✔️ N 2 2 ✔️ O 6 6 ✔️ S 3 3 ✔️
Step 3: Verify that the equation is balanced
Since there are an equal number of atoms of each element on both sides, the equation is balanced.
2HNO3 + 3H2S = 2NO + 3S + 4H2OPractice Balancing
HNO3 - + + H2S - + = NO - + + S - + + H2O - +Reactants | Products | ||
---|---|---|---|
H | 3 | 2 | ❌ |
N | 1 | 1 | ✔️ |
O | 3 | 2 | ❌ |
S | 1 | 1 | ✔️ |
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