How Much Volume Of CO2 At STP Is Liberated By The Combustion ...

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• How much volume of CO2 at STP ...

AnswerQuestion Answers for Class 12Class 12 BiologyClass 12 ChemistryClass 12 EnglishClass 12 MathsClass 12 PhysicsClass 12 Social ScienceClass 12 Business StudiesClass 12 EconomicsQuestion Answers for Class 11Class 11 EconomicsClass 11 Computer ScienceClass 11 BiologyClass 11 ChemistryClass 11 EnglishClass 11 MathsClass 11 PhysicsClass 11 Social ScienceClass 11 AccountancyClass 11 Business StudiesQuestion Answers for Class 10Class 10 ScienceClass 10 EnglishClass 10 MathsClass 10 Social ScienceClass 10 General KnowledgeQuestion Answers for Class 9Class 9 General KnowledgeClass 9 ScienceClass 9 EnglishClass 9 MathsClass 9 Social ScienceQuestion Answers for Class 8Class 8 ScienceClass 8 EnglishClass 8 MathsClass 8 Social ScienceQuestion Answers for Class 7Class 7 ScienceClass 7 EnglishClass 7 MathsClass 7 Social ScienceQuestion Answers for Class 6Class 6 ScienceClass 6 EnglishClass 6 MathsClass 6 Social ScienceQuestion Answers for Class 5Class 5 ScienceClass 5 EnglishClass 5 MathsClass 5 Social ScienceQuestion Answers for Class 4Class 4 ScienceClass 4 EnglishClass 4 MathsHow much volume of $C{O_2}$ at S.T.P is liberated by the combustion of 100 $c{m^3}$ of propane $({C_3}{H_8})$?A. 100 $c{m^3}$B. 200 $c{m^3}$C. 300 $c{m^3}$D. 400 $c{m^3}$AnswerVerified559.5k+ viewsHint: The elements in nature exist in one of the three states, solid, liquid or gas. The gases are the freest in their mobility while the solids are the most rigid. All these properties arise from the intermolecular forces of attraction that act between the molecules and atoms of the elements. All the reactions that take place are along with a specific ratio in which the elements react.Complete step by step answer:S.T.P is the acronym for the standard temperature and pressure. It defines the state in which the temperature and pressure are defined and the volume taken by any gas is found to be 22.4 L.1 mole of all the gases at S.T.P is found to acquire a volume of 22.4L.The chemical reaction that will take place in the above question can be stated as follows${C_3}{H_8} + 5{O_2} \to 3C{O_2} + 4{H_2}O$Analysing the above reaction and using the stoichiometric coefficients we see that we get 3 times the carbon dioxide of the propane used. So for 1-mole propane used we get 3 moles of carbon dioxide. The volume of 1-mole gas at STP is 22.4LThe moles of 100 $c{m^3}$ propane gas will be $\dfrac{{100c{m^3}}}{{22.4}}$ Thus 100 $c{m^3}$ of propene at STP will form $\dfrac{{100c{m^3}}}{{22.4}} \times 3 \times 22.4L$$ = 300c{m^3}$ at STP of carbon dioxide.so, the correct answer to the above question is C.Note: Charles law is a gas law which is derived after experimentation. It describes how gases tend to increase in volume when they are heated. The law states that, when the pressure of the gas is held constant, the kelvin temperature and the volume of the gas will be directly proportional. This law can be mathematically stated as$\dfrac{{{V_1}}}{{{T_1}}} = \dfrac{{{V_2}}}{{{T_2}}}$Where ${V_1}$ is the first volume and ${V_2}$ is the second volume. Similarly, ${T_1}$ is the first temperature and ${T_2}$ is the second temperature.Recently Updated PagesMaster Class 11 Computer Science: Engaging Questions & Answers for SuccessMaster Class 11 Business Studies: Engaging Questions & Answers for SuccessMaster Class 11 Economics: Engaging Questions & Answers for SuccessMaster Class 11 Social Science: Engaging Questions & Answers for SuccessMaster Class 11 Chemistry: Engaging Questions & Answers for SuccessMaster Class 11 English: Engaging Questions & Answers for SuccessMaster Class 11 Computer Science: Engaging Questions & Answers for SuccessMaster Class 11 Business Studies: Engaging Questions & Answers for SuccessMaster Class 11 Economics: Engaging Questions & Answers for SuccessMaster Class 11 Social Science: Engaging Questions & Answers for SuccessMaster Class 11 Chemistry: Engaging Questions & Answers for SuccessMaster Class 11 English: Engaging Questions & Answers for Success

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