Is X/m(m^2 + N^2 + K^2) = Xm + Yn + Zk? (1) Z/k = X/m (2) - GMAT Club

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Back to Forum Create Topic Reply Is x/m(m^2 + n^2 + k^2) = xm + yn + zk? (1) z/k = x/m (2) ValleyBall1 ValleyBall1 Joined: 26 Jul 2005 Last visit: 18 Nov 2011 Posts: 208 Location: Los Angeles Posts: 208 Post URL 27 Oct 2005, 15:35 Show timer 00:00 Start Timer Pause Timer Resume Timer Show Answer a0% b20% c60% d0% e20% A B C D E Hide Show History My Mistake Official Answer and Stats are available only to registered users. Register/Login. Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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60% (04:02) correct 40% (01:58) wrong based on 5 sessions

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Date Time Result Not Attempted Yet Is x/m(m^2 + n^2 + k^2) = xm + yn + zk?(1) z/k = x/m(2) x/m = y/nOPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-m-m-2-n-2-k-2-xm-yn-zk-99423.html Archived Topic Hi there, This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here. Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions. Thank you for understanding, and happy exploring! ShowHide Answer Official Answer Official Answer and Stats are available only to registered users. Register/Login. Kudos Add Kudos 1 Bookmarks Bookmark this Post conocieur conocieur Joined: 20 Mar 2005 Last visit: 21 Nov 2006 Posts: 103 Location: Colombia, South America Posts: 103 Post URL 27 Oct 2005, 15:49 I think is C x/m(m^2 + n^2 + z^2) = xm + yn + zk that is equal to xm + xn^2/m + xz^2/n = xm + yn + zk from I: x/m = y/n then xn = ym and from there (xn*n)/m is equal to ym*n/m equal to yn so insuff from ii, do the same stuff as i and you get zk so insuff taking both it works so C Kudos Add Kudos Bookmarks Bookmark this Post ValleyBall1 ValleyBall1 Joined: 26 Jul 2005 Last visit: 18 Nov 2011 Posts: 208 Location: Los Angeles Posts: 208 Post URL 28 Oct 2005, 14:54 Right again - OA is C. Kudos Add Kudos Bookmarks Bookmark this Post Study1 Study1 Joined: 14 Sep 2010 Last visit: 06 Jan 2019 Posts: 8 Posts: 8 Post URL 18 Nov 2011, 02:39 Is x/m(m^2 + n^2+ k^2) = xm + yn + zk? xm^2 + xn^2 + xk^2 = xmm +ynm +zkm?Is xn^2 + xk^2 = ynm + zkm?(1) z/k = x/m (xk = mz)xk^2 = (xk)k = (mzk)xn^2 + xk^2 = ynm + zkm =xn^2 = ynm?xn = my?(2) x/m = y/n (xn = my)xn^2 = (xn)n = (my)nxn^2 + xk^2 = ynm + zkm =xk^2 = zkm?xk = mz?Put (1) and (2) together xn^2 + xk^2 = ynm + zkm =(my)n + (mz)k = ynm + zkmBoth statements used = Answer CPosted from my mobile device Kudos Add Kudos Bookmarks Bookmark this Post BDSunDevil BDSunDevil Joined: 13 May 2011 Last visit: 24 Dec 2017 Posts: 142 WE 1: IT 1 Yr WE 2: Supply Chain 5 Yrs Posts: 142 Post URL 18 Nov 2011, 04:19 is xm^2+xn^2+xk^2=xm^2+ynm+zkmi. e. xn^2+xk^2=ynm+zkmstatement 1: xk=zm xn^2=ynm Not SufficientStatement 2: ym=xn xk^2=zkm Not SufficientTogether: xn^2+xk^2=xn^2+xk^2Sufficient Kudos Add Kudos Bookmarks Bookmark this Post Bunuel Bunuel Math Expert Joined: 02 Sep 2009 Last visit: 28 Nov 2024 Posts: 97,392 Products: Expert reply Active GMAT Club Expert! Tag them with @ followed by their username for a faster response. Posts: 97,392 Post URL 23 Nov 2017, 06:43 Is \(\frac{x}{m}*(m^2+n^2+k^2)=xm+yn+zk\)?Multiply both part by \(m\), to get rid of fraction part and open the brackets: is \(xm^2+xn^2+xk^2=xm^2+ynm+zkm\)?\(xm^2\) will cancel out and the question becomes: is \(xn^2+xk^2=ynm+zkm\)?(1) \(\frac{z}{k}=\frac{x}{m}\) --> \(zm=kx\) --> substitute zm with kx --> is \(xn^2+xk^2=ynm+xk^2\) --> \(xk^2\) will cancel out and the question becomes is "\(xn^2=ynm\)?" Not sufficient.(2) \(\frac{x}{m}=\frac{y}{n}\) --> \(xn=ym\) --> substitute ym with xn --> is \(xn^2+xk^2=xn^2+zkm\) --> \(xn^2\) will cancel out and the question becomes "is \(xk^2=zkm\)?" Not sufficient.(1)+(2) is \(xn^2+xk^2=ynm+zkm\)? --> substitutein from (1) and (2) --> is \(xn^2+xk^2=xn^2+xk^2\)? Answer is YES. Sufficient.Answer: C.OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-m-m-2-n-2-k-2-xm-yn-zk-99423.html Archived Topic Hi there, This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here. Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions. Thank you for understanding, and happy exploring! _________________ New to the GMAT Club?

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